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3 years ago

7

can you guys help me?The expression 12(x + 4) represents the total number of shirts Viviana bought in April and May at $12 each.

Which property is applied to write the equivalent expression 12x + 48? pleas and thank you

1 answer:

Degger [83]3 years ago

8 0

The distributive property

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I’m completely lost can anybody help solve this

Marizza181 [45]

Answer:

$\huge\boxed{x=54^o}$

Step-by-step explanation:

<em>Look at the picture.</em>

<em />

We have:

$l=108^o$

Therefore

$2\alpha=108^o$ <em>divide both sides by 2</em>

$\dfrac{2\alpha}{2}=\dfrac{108^o}{2}\\\\\alpha=54^o$

7 0

4 years ago

Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco

kari74 [83]

Answer:

C. $\frac{1}{18}$

Step-by-step explanation:

Given: Six cards numbered from $1$ to $6$ are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is $8$ , what is the probability that one of the two cards drawn is numbered $5$ .

Solution:

Sample space for sum of cards when two cards are drawn at random is $\{(1,1),(1,2),(1,3)......(6,6)\}$

total number of possible cases $=36$

Sample space when sum of cards is $8$ is $\{(3,5),(5,3),(6,2),(2,6),(4,4)\}$

Total number of possible cases $=5$

Sample space when one of the cards is $5$ is $\{(5,3),(3,5)\}$

Total number of possible cases $=2$

Let A be the event that sum of cards is $8$

$p(\text{A})$ $=\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}$

$p(\text{A})=\frac{5}{36}$

Let B be the event when one of the two cards is $5$

probability than one of two cards is $5$ when sum of cards is $8$

$p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}$

$p(\frac{\text{B}}{\text{A}})=\frac{2}{5}$

Now,

probability that sum of cards $8$ is and one of cards is $5$

$p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})$

$p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}$

$p(\text{A and B})=\frac{1}{18}$

if sum of cards is $8$ then probability that one of the cards is $8$ is $\frac{1}{18}$ , option C is correct.

3 0

3 years ago

Any help at all would be deeply appreciated. i am DESPERATE

Lana71 [14]

The answers are C and D.

6 0

3 years ago

Six by the power of 2×3

Sergio039 [100]

Answer:

46,656

Step-by-step explanation:

6^2x3=

6^6=

6x6x6x6x6x6=

46,656

Hope that helps!

5 0

2 years ago

Read 2 more answers

The sum of two number is 17. their driffrence is 27.write a system of equations that describe this situation. solve to find the

STatiana [176]

A) x + y = 17
B) x - y = 27
Adding both equations:2x = 44
x = 22
y = -5

6 0

3 years ago