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igomit [66]
3 years ago
15

Draw the image of the following segment after a dilation centered at the origin with a scale factor of 2/3

Mathematics
1 answer:
Irina18 [472]3 years ago
5 0

Answer:

Step-by-step explanation:

Let the ends of the given segment are A and B.

Coordinates of A → (8, 6)

Coordinates of B → (12, 12)

If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,

(x, y) → (kx, ky)

If k = \frac{2}{3}

(x, y) → (\frac{2}{3}x, \frac{2}{3}y)

By this rule coordinates of the image points of A and B will be,

A(8, 6) → A'(\frac{2\times 8}{3},\frac{2\times 6}{3})

           → A'(5.3, 4)

B(12, 12) → B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})

             → B'(8, 8)

Now we can get the image of segment AB after dilation by a scale factor of \frac{2}{3}.

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Consider the tables that represent ordered pairs corresponding to a function and its inverse. When comparing the functions using
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D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Step-by-step explanation:

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A

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