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kipiarov [429]
3 years ago
5

The question is in the image

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

The first one

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

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Help 9th grade algebra
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Answer:

Step-by-step explanation:

1. true

2. true

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3 years ago
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A baseball is hit so that the height above the ground is given by the equation h=-16t^2+96t+3, where h is the height in feet and
Alexus [3.1K]
H'=-32t+96
0=-32t+96
-96=-32t
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3 seconds

H=-16t^2+96t+3
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6 0
3 years ago
-5x + 12 - 7x = -3(5x + 8)
nikitadnepr [17]

Simplify -5x + 12 - 7x to -12x + 12

-12x + 12 = -3(5x + 8)

Expand

-12x + 12 = -15x - 24

Add 15x to both sides

-12x + 12 + 15x = -24

Simplify 12x + 12 + 15x to 3x + 12

3x + 12 = -24

Subtract 12 from both sides

3x = -24 - 12

Simplify -24 - 12 to -36

3x = -36

Divide both sides by 3

x = -36/3

Simplify 36/3 to 12

<u>x = -12</u>

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3 years ago
What is 50.8 divided by 2.54
Veseljchak [2.6K]
It's 20.

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Suppose that X is a random variable that has a binomial uncertainty distribution with parameters n = 10 and π = 0.4. Calculate t
swat32

The numerical values of the mean and standard deviation are 4 and 1.55, respectively

<h3>The numerical value of the probability that x = 6. </h3>

The given parameters are:

n = 10

π = 0.4

The probability is then calculated as:

P(x) = ^nC_x * \pi^x *(1-\pi)^{n-x}

So, we have:

P(6) = ^{10}C_6 * 0.4^6 *(1-0.4)^4

Apply the combination formula

P(6) = \frac{10!}{6!4!} * 0.4^6 *0.6^4

So, we have:

P(6) = 210 * 0.4^6 *0.6^4

Evaluate

P(6) = 0.1115

Hence, the numerical value of the probability that x = 6 is 0.1115

<h3>The numerical values of the mean and standard deviation </h3>

The mean value is:

\bar x = n\pi

This gives

\bar x = 10 * 0.4

\bar x = 4

The standard deviation value is:

\sigma = \sqrt{\bar x(1-\pi)

This gives

\sigma = \sqrt{4(1-0.4)

\sigma = 1.55

Hence, the numerical values of the mean and standard deviation are 4 and 1.55, respectively

Read more about mean and standard deviation at:

brainly.com/question/16030790

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