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saul85 [17]
2 years ago
6

Will mark brainliest​

Mathematics
1 answer:
grandymaker [24]2 years ago
7 0

Answer:

66!!!!

Step-by-step explanation:

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One zero of x^3 - 4x = 0 is 0 what are the other zeros of the function
myrzilka [38]
So you have x^3 - 4x = 0. What you can do is pull out an x from both x^3 and - 4x so it looks like this:

x( {x}^{2} - 4) = 0

Then you can find a number that makes the part inside the parentheses turn into zero. For beginners, it may be easier to write it out seperately and solve for x.

{x}^{2} - 4 = 0

We need to solve for x, so the first step is to add 4 to both sides, so we get something like this:

{x}^{2} = 4

Then, we can square root both sides to get rid of the power on the x, so it looks like this:

x = \sqrt{4}

Now, every square root has two answers, a positive and a negative. If we look at the bottom example:

{2}^{2} = 4

{( - 2)}^{2} = 4

We can see that both -2 and 2 to the power of two will equal to 4.

So finally, we get:

x = - 2 \: and \: 2

These are the other 'Zero's for the original function. If you are not sure of what a 'Zero' is, it is where the function crosses over the x-axis on a graph.
5 0
2 years ago
Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr
dybincka [34]

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

3 0
3 years ago
0.000007 in standform
Murljashka [212]

Answer:

7.0 x 10 to the 6th

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which quadratic function in vertex form can be represented by the graph that has a vertex at (3, -7) and passes through the poin
mrs_skeptik [129]
The equation is y=-3/4(x-3)^2-7
6 0
2 years ago
Y=x3 is that a function?
kotykmax [81]

Answer:

yes

Step-by-step explanation:

y(x) is even or odd according as y(−x)=±y(x) . Here, #y(-x)=-(-x)^3=-(-x^3)=x^3=-y(x). So, y is an odd function of x.

5 0
2 years ago
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