Question

Use the elimination method to find all solutions of the system:

Answer 1

Answer:

$x = 3$    and    $y = 4$

Step-by-step explanation:

Given

[Correct Question]

$x^2 - 2y = 1$

$x^2 + 5y = 29$

Required

Solve using elimination

First, we eliminate x.

Subtract equation (1) from (2)

$x^2 - x^2 + 5y - (-2y) = 29 - 1$

$5y - (-2y) = 28$

$5y +2y = 28$

$7y = 28$

Divide through ny 7

$y = 4$

Take $x^2 - 2y = 1$

Make x^2 the subject

$x^2 = 1 + 2y$

Substitute 4 for y

$x^2 = 1 + 2*4$

$x^2 = 1 + 8$

$x^2 = 9$

Take square roots

$x = \sqrt 9$

$x = 3$