Ask question

Ask question

All categories

sleet_krkn [62]

3 years ago

5

the population of staten island is 7.610^3. the population of Brooklyn is 2.310^5. how many people are there in Brooklyn and S

taten Island?

1 answer:

alukav5142 [94]3 years ago

6 0

Answer:

1

Step-by-step explanation:

1

You might be interested in

4(2-4x)-3x=65 Whats the answer and how did you solve it?

IRINA_888 [86]

Answer:

x= -3

Step-by-step explanation:

Distribute 4(2-4x) which leaves you with 8-16x-3x=65

combine the like terms which leaves you with 8-19x=65

subtract 8 from both sides 8-19x-8=65-8 which leaves you with -19x=57

lastly divide -19 from both sides which leaves you with x= -3

3 0

3 years ago

A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to

Nesterboy [21]

Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$6\%=\frac{6}{100}=0.06$

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

$1000=P(1+\frac{0.06}{0.5})^{0.5*6}$

$1000=P(1+0.12)^{3}$

$1000=P(1.12)^{3}$

$1000=P*1.404928$

$\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}$

$P=711.7802478$

$P\approx 712$

Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

7 0

3 years ago

[5x+6]*{(3%*5.0x)*5(7*8c)}

Diano4ka-milaya [45]

Answer:

210x²c+252xc

Step-by-step explanation:

3 0

2 years ago

Factor the expression.<br> 3x2 + 14x-5

Irina18 [472]

Answer:

(3x-1)(x+5)

Step-by-step explanation:

Find two numbers that when they multiply, you get the third term,

which is -5 in this problem. And when they add up, you get the second term,

which is 14 in this problem.

8 0

3 years ago

Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen

vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

6 0

3 years ago