Answer:
the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector
Explanation:
Given that:
The area vector of a square loop has 5 numbers of turns i.e n = 5
each with side length = 0.2 m
Current I = 2 A
uniform magnetic field = 50.0 T
Now; the magnitude of the total magnetic field B is calculated as :
B = IA
where;
I = current
A = area ( n × l²)
B = I ( n × l²)
B = 2 × 5 × 0.2²
B = 0.4 Am²
The direction of the magnetic moment is antiparallel to the area vector;
Hence ; the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector
So here, you're looking for distance. The formula is D=vt+1/2at^2.
Lets plug in the informations.
10 m/s is our v (initial velocity)
5 second is out t(time)
3.2 m/s is our a(acceleration)
10m/s(5)+1/2(3.2m/s+5^2)
50m/s+1/2(28.2)
50m/s+14.1
Answer =64.1 m
Glad to help you out buddy. Let me know if you need help.
electricity can't flow anymore if the wire isnt connected at the beginning
It's easy to roll the the basket ball than bowling ball
It is because bowling ball is solid spherical ball which will have less moment of inertia
its moment of inertia is given as
While for the hollow ball like basketball we know that moment of inertia is given as
so here we can see for the same mass if we take basketball then its moment of inertia is more so it is easy to roll basket ball then to roll bowling ball.
So it is easy to roll basket ball then rolling ball
The tension in the string when the ball is at the bottom of the path is 2.61 Newtons.
<h3>Tension</h3>
A tension is simply referred to as a force along the length of a flexible medium such as strings, cable, ropes etc.
Tension in a string revolving can be determined using the expression;
T = mv² / r
Where m is mass of object, v is velocity and r is radius ( length of string )
Given the data in the question;
- Radius ( length of string ) r = 97.7cm = 0.977m
- Tension in the string; T = ?
To determine tension in the string, we substitute our given values into the expression above.
T = mv² / r
T = (0.182kg × (3.74m/s)²) / 0.977m
T = (0.182kg × 13.9876m²/s²) / 0.977m
T = (2.5457432kgm²/s²) / 0.977m
T = 2.61kgm/s²
T = 2.61N
Therefore, the tension in the string when the ball is at the bottom of the path is 2.61 Newtons.
Learn more about Tension here: brainly.com/question/14351325
