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ella [17]
4 years ago
10

According to Newton’s law of universal gravitation, which statements are true?

Physics
2 answers:
Ostrovityanka [42]4 years ago
7 0

<u>Answer</u>

A) As we move to higher altitudes, the force of gravity on us decreases.


<u>Explanation</u>

Gravitational force is the force of attraction between two bodies that given masses.

Gravitational force of the earth exists between the earth and other objects close to it.

This force is inversely to the square of distance between them. This means as the distance between the earth and the object increases, the gravity decreases.

∴ the correct answer is: A) As we move to higher altitudes, the force of gravity on us decreases.


Irina-Kira [14]4 years ago
3 0

A) As we move to higher altitudes, the force of gravity on us decreases.

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The sun is made mostly up of Hydrogen.
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4 years ago
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A 7.26kg bowling ball (16 pounds) is at rest what is the net force on the bowling ball
cestrela7 [59]
Well since the bowling ball is at rest and is not moving at all, and assuming that the ball is on an even surface, the Fg is equal to the FN = normal force, and thus all forces are balanced, the Fnet = 0.
5 0
3 years ago
What has alternating electric and magnetic fields that travel in the form of a wave?
8_murik_8 [283]

Option (B)is correct.

Alternating electric and magnetic fields has electromagnetic radiation that travel in the form of a wave.

The varying or alternating electric field produces the varying magnetic field.This varying magnetic field in turn produces varying electric field . Thus these varying electric and magnetic fields travel in the form of electromagnetic waves. These electromagnetic waves travel with the velocity of light.These are transverse in nature.

8 0
4 years ago
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A garden hose with an inside diameter of 0.75 inches is used to fill a round swimming pool 3.0 m in diameter. How many hours wil
bagirrra123 [75]

Answer:

23

Explanation:

First, we need to convert the hose diameter from inches to meters.

0.75 in × (2.54 cm / in) × (1 m / 100 cm) = 0.0191 m

Calculate the flow rate given the velocity and hose diameter:

Q = vA

Q = v (¼ π d²)

Q = (0.30 m/s) (¼ π (0.0191 m)²)

Q = 8.55×10⁻⁵ m³/s

Find the volume of the pool:

V = π r² h

V = π (1.5 m)² (1.0 m)

V = 7.07 m³

Find the time:

t = V / Q

t = (7.07 m³) / (8.55×10⁻⁵ m³/s)

t = 82700 s

t = 23 hr

3 0
3 years ago
A student that jumps a vertical height of 50 cm during the hang time activity.
muminat

The hang time of the student is 0.64 seconds, and he must leave the ground with a speed of 3.13 m/s

Why?

To solve the problem, we must consider the vertical height reached by the student as max height.

We can use the following equations to solve the problem:

<u>Initial speed calculations:</u>

v_{f}^{2}=v_{o}^{2}+2*a*d

At max height, the speed tends to zero.

So, calculating, we have:

<u>v_{f}^{2}=v_{o}^{2}+2*a*d\\\\0=v_{o}^{2}+2*(-9.81\frac{m}{s^{2}})*0.5m\\\\v_{o}^{2}=9.81\frac{m^{2} }{s^{2}}\\\\v_{o}=\sqrt{9.81\frac{m^{2} }{s^{2}}}=3.13\frac{m}{s}</u>

<u>Hang time calculations:</u>

We must remember that the total hang time is equal to the time going up plus the time going down, and both of them are equal,so, calculating the time going down, we have have:

y-yo=vo.t+\frac{1}{2}*9.81\frac{m}{s^{2}}*t^{2} \\\\0.5m-0=0*t+4.95*t^{2}\\\\t^{2}=\frac{0.5}{4.95}\\\\t=\sqrt{0.101}=0.318s

Then, for the total hang time, we have:

TotalHangTime=2*0.318seconds=0.64seconds

Have a nice day!

3 0
4 years ago
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