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3 years ago

Easy defimation of newtons second law of motion

1 answer:

8 0

Hi pupil here's your answer ::

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Newton's Second Law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force.
ie., F=ma

Where F is the force applied, m is the mass of the body, and a, the acceleration produced.

Or in simplest language it is the force applied to a particular object of particular mass multiplied by the acceleration caused by force .

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hope that it helps. . . . . .

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The sound intensity level from one solo flute is 70 dB. If 10 flutists standing close together play in unison, what will the sou

Masja [62]

Answer:

80 dB

Explanation:

$I_0$ = Threshold intensity = $10^{-12}\ W/m^2$

I = Intensity of sound

$\beta$ = Intensity level of sound = 70 dB

Intensity level of sound is given by

$\beta=10log\dfrac{I}{I_0}\\\Rightarrow 70=10log\dfrac{I}{I_0}\\\Rightarrow \dfrac{70}{10}=log\dfrac{I}{10^{-12}}\\\Rightarrow 10^{\dfrac{70}{10}}=\dfrac{I}{10^{-12}}\\\Rightarrow \dfrac{I}{10^{-12}}=10^{\dfrac{70}{10}}\\\Rightarrow I=10^{7}\times 10^{-12}\\\Rightarrow I=10^{-5}\ W/m^2$

If there are 10 flutes $I=10\times 10^{-5}\ W/m^2$

$\beta=10log\dfrac{10\times 10^{-5}}{10^{-12}}\\\Rightarrow \beta=10log10^8\\\Rightarrow \beta=10\times 8\\\Rightarrow \beta=80\ dB$

The sound intensity level is 80 dB

5 0

3 years ago

Derive a relation between time period anf frequency of a wave

Elza [17]

Answer:

The relation between frequency and time period is given by:

f = 1/T

Explanation:

In a wave motion, the particle move about the mean position with the passage of time. The particles rise to reach the highest point which is crest, and similarly falls to reach the lowest point which is trough. The cycle keeps on repeating.

The time period of the wave can be defined as the time taken to complete one such cycle. Time period is given by:

T = 2π/ω

Frequency can be defined as the number of cycles completed in unit time, which can be taken as the inverse of time period. frequency is given by

f = ω/2π

f = 1/T

8 0

3 years ago

A 5.5kg mass is pushed with a force of 31N across a table having μk of 0.350. Find how fast it will accelerate, taking friction

Ipatiy [6.2K]

Answer:

3.66m/s^2

Explanation:

First, we need to find the friction which is F=u*N.

After that, find the resultant force by substarcting the friction from the forward force.

Lastly,using the formula F=ma, substitute in the known values of F and m to find a

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3 years ago

Pani-rosa [81]

The answer would be center of mass, B

8 0

3 years ago

Read 2 more answers

Question 2 The gravitational force between two objects with identical masses that are 10 m apart, is 2.67 x10-10 N. To the neare

xxMikexx [17]

Answer 888990,0 kg

Explanation:

3 0

3 years ago