We know that
∠ TSR = 84°
if SQ bisects ∠ <span>TSR
then
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>
</span>
I’m not positive but I think all you have to do is minus 62 from 180 which would be 119
D.........................................
Answer:
y ≈ 5.2
Step-by-step explanation:
∠ F = 180° - (42 + 48)° ← sum of angles in a triangle
∠ F = 180° - 90° = 90°
Thus Δ DEF is right at F
Using the sine ratio in the right triangle
sin48° =
=
=
( multiply both sides by 7 )
7 × sin48° = y , then
y ≈ 5.2 ( to the nearest tenth )