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2 years ago

Brainliest fir CORRECT answer

Mathematics

1 answer:

viktelen [127]2 years ago

4 0

Answer:

y ≈ 5.2

Step-by-step explanation:

∠ F = 180° - (42 + 48)° ← sum of angles in a triangle

∠ F = 180° - 90° = 90°

Thus Δ DEF is right at F

Using the sine ratio in the right triangle

sin48° = $\frac{opposite}{hypotenuse}$ = $\frac{DF}{DE}$ = $\frac{y}{7}$ ( multiply both sides by 7 )

7 × sin48° = y , then

y ≈ 5.2 ( to the nearest tenth )

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Answer:

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2 years ago

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svetlana [45]

Answer:

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3 years ago

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2 years ago

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11111nata11111 [884]

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Step-by-step explanation:

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2 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago

Brainliest fir CORRECT answer ​

Brainliest fir CORRECT answer