1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tems11 [23]
3 years ago
14

A total of 76 students responded to a survey about transportation to school. Of the girls surveyed, 22 walk to school and 29 get

a ride. Of the 25 boys surveyed, 9 get a ride to school. Construct a two-way frequency table to display the data. Drag the numbers into the boxes. Each number may be used once, more than once, or not at all.​
Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answers:

From as I can see. You need to do a long division on 76 and 9 and then if you got the answer subtract the answer with the girls surveyed and you'll get the answer and multiply the answer with the boys surveyed and then add all the answers together. Hoped this help!!! :)

You might be interested in
Denis let go of a penny at the top of a well and the penny fell straight down to the bottom of the well the top of the well was
Furkat [3]

Answer:

The distance between the top of the well and the bottom of the well was 12 1/2

Step-by-step explanation:

(a.k.a B) i did it and got it right :)

8 0
3 years ago
Anyone know the answer?​
Aleksandr-060686 [28]
I’m pretty sure it’s d but i’m not 100%
5 0
3 years ago
X power to 11 +101 divisible by x+1 then what is the remainder
emmasim [6.3K]

Answer:

110

Step-by-step explanation:

Let's define P(x) = x^{11} + 101. So when we divide it by 'x+1', we can use Bezout's Theorem which states: that any polynomial(P(X)) divided by another binomial in the form 'x - a', then the remainder will be P(a).

We can use this fact to determine the remainder, because we divided our P(X) by x + 1 which is the same as x - (-1). So we plug in P(-1).

P(-1) = (-1)^11 + 101 = -1 + 101 = 110

6 0
3 years ago
Rico and his friend eat some lasagna. Rico eats 1/9 of lasagna, and his friend eats 1/18 of the lasagna. How much of the lasagna
Blizzard [7]

Answer:

\frac{5}{6} of the lasagna is left

<u>Step-by-step explanation:</u>

Given:

Amount of lasagna Rico eats = 1/9

Amount of lasagna His friend eats = 1/18

To Find:

The amount  lasagna is left =?

Solution:

Total lasagna ate by both Rico and his friend = Amount of lasagna Rico eats +  Amount of lasagna His friend eats

Total lasagna ate by both Rico and his friend = \frac{1}{9} + \frac{1}{18}

Total lasagna ate by both Rico and his friend = \frac{2}{19} + \frac{1}{18}

Total lasagna ate by both Rico and his friend = \frac{3}{18}

Total lasagna ate by both Rico and his friend = \frac{1}{6}

The amount  lasagna is left = 1 - Total lasagna ate by both Rico and his friend.

The amount  lasagna is left = 1 - \frac{1}{6}

The amount  lasagna is left =\frac{6-1}{6}

The amount  lasagna is left =\frac{5}{6}

4 0
3 years ago
5.3.PS-/<br> Simplify the expression.<br> -<br> -2.8f + 0.8f – 16 - 9
bezimeni [28]
=-2f-25 is your answer
8 0
3 years ago
Other questions:
  • Helppppp pleaseeeeeee
    9·2 answers
  • Each of four friends orders a sweatshirt from a catalog. There are 14 colors of sweatshirts, 7 of which are all cotton and 7 of
    11·1 answer
  • AYUDAA es para hoyyy Un avión volaba a 14.800 metros de altura . Primero , bajo a 23.000 decímetros y luego 54 hectometros más a
    6·1 answer
  • Which is the definition of a line segment?
    9·1 answer
  • Find the value of C<br>​
    9·1 answer
  • Solve:
    7·2 answers
  • Write each expression using exponents.<br> 3/8 * 3/8 * 3/8=
    15·2 answers
  • Which of the following expressions to 36x + 24y? choose all that apply.
    15·1 answer
  • Given the expressions are equivalent (3x + 2)^2 - (mx^2 + 7) = 5x^2 + 12x - 3 2 - 3 What is the value of m?​
    11·1 answer
  • If XY is 4 m and WZ is 9 m, the exact volume of the cone is ___ pi square meters
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!