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2 years ago

What can be used to explain a statement in a geometric proof

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

7 0

Answer:

corollary,postulate,theorem,definition

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Encuentre el radio y el área de círculos cuya circunferencias tienen las siguientes medidas

Vadim26 [7]

Answer:

Los radios de los círculos son $r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$ , respectivamente.

Las áreas de los círculos son $A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$ , respectivamente.

Step-by-step explanation:

La circunferencia ( $s$ ) se calcula mediante la siguiente fórmula:

$s = 2\pi\cdot r$ (1)

Donde $r$ es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica ( $A$ ) mediante la siguiente fórmula:

$A = \pi\cdot r^{2}$ (2)

Si conocemos que las circunferencias son $s_{1} = 62.8$ , $s_{2} = 12.65$ y $s_{3} = 47.7$ , respectivamente:

1) Radios de los círculos

$r_{1} = \frac{s_{1}}{2\pi}$ , $r_{2} = \frac{s_{2}}{2\pi}$ , $r_{3} = \frac{s_{3}}{2\pi}$

$r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$

2) Áreas de los círculos

$A_{1} = \pi\cdot r_{1}^{2}$ , $A_{2} = \pi\cdot r_{2}^{2}$ , $A_{3} = \pi\cdot r_{3}^{2}$

$A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$

6 0

3 years ago

Lydia drove 216 miles and used 6 gallons of gasoline on a recent trip. Which of the following represents the unit rate of gasoli

yulyashka [42]

Step-by-step explanation:

is their an attachment for the problem?

7 0

3 years ago

Read 2 more answers

Simplify the problem.

lesya [120]

Answer:

Option 4: 4¹¹

Step-by-step explanation:

Looking at the problem, I need to work out 4⁴ squared first, which is the same as 4⁸. Then multiply that by 4³ to get 4¹¹. What I did was simply add 3 + (4 * 2), which is 11.

7 0

2 years ago

A 20 ft. ladder is used against a 15 ft. wall. What is the measure of the angle made by the ladder and the ground (nearest whole

Brrunno [24]

Step-by-step explanation:

Given that,

The length of a ladder, H = 20 feet

The height of the wall, h = 15 ft

We know that,

$\sin\theta=\dfrac{h}{H}$

h is perpendicular and H is hypotenuse

So,

$\sin\theta=\dfrac{15}{20}\\\\\theta=\sin^{-1}(\dfrac{15}{20})\\\\\theta=48.59^{\circ}$

Now using Pythagoras theoerm,

$b=\sqrt{H^2-h^2}\\\\b=\sqrt{20^2-15^2}\\\\b=13.2\ ft$

Hence, the angle made by the ladder and the ground is 48.59° and the ladder is 13.2 feet from the wall on the ground.

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3 years ago

What is the solution for the equation? 14.8 = n minus 0.3

Ymorist [56]

Answer:

15.1

Step-by-step explanation:

14.8=n-.3

you'd add .3 to other side so it'd be 15.1

5 0

3 years ago