Answer:
The equation for rational function for given asymptotes is
f(x)=(-4x^2-6)/{(x-3)(x+3)}
Step-by-step explanation:
Given:
vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at
y=-4 i.e parallel to x axis.
To find:
equation of a rational function i.e function in form p/q
Solution;
the equation should be in form of p/q
Numerator :denominator.
Consider f(x)=g(x)/h(x)
as vertical asymptote are x=-3 and x=3
denominator becomes, (x-3) and (x+3)
for horizontal asymptote to exist there should have same degrees in numerator and denominator which of '2'
when g(x) will be degree '2' with -4 as coefficient and dont have any real.
zero.
By horizontal asymptote will be (-4x^2 -6)
The rational function is given by
f(x)=g(x)/h(x)
={(-4x^2-6)/(x-3)(x+3)}.
Perimeter= 2 ( length + width)
2×(12+6)
2×18
=36
Answer:
x= 5
Step-by-step explanation:
You need to get rid of the fraction first and to do that you muliply the whole equation by 5 so that your new equation reads 4x+25=45. Then you subtract 25 from both sides so you have 4x=20. Divide both sides by 4 so x=5.
9514 1404 393
Answer:
20.3
Step-by-step explanation:
The distance formula can be used to find the side lengths.
d = √((x2 -x1)^2 +(y2 -y1)^2)
For the first two points, ...
d = √((3 -(-2))^2 +(6 -3)^2) = √(5^2 +3^2) = √34 ≈ 5.83
For the next two points, ...
d = √((2 -3)^2 +(-2-6)^2) = √(1 +64) = √65 ≈ 8.06
For the last and first points, ...
d = √((-2-2)^2 +(3-(-2)^2) = √(16 +25) = √41 ≈ 6.40
Then the sum of the side lengths is ...
5.83 +8.06 +6.40 = 20.29 ≈ 20.3
The perimeter of the triangle is about 20.3 units.
Since the expression 7h + 1.50d can be used to find the total earnings. We just need to substitute the given data to the expression to solve the problem.
7(15) + 1.50(8)
105 + 12 = 117
Colton's total earnings after working 15 hours and making 8 deliveries is 117 dollars.
