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ki77a [65]
3 years ago
13

What is the voltage drop across R4 in the diagram shown above?

Computers and Technology
1 answer:
pickupchik [31]3 years ago
3 0
R₂ and R₃ can be replaced by:

R_5 =  \frac{1}{\frac{1}{R_2} + \frac{1}{R_3}} = 106 \frac23

The total R of the circuit is R₁+R₅+R₄ = 706 2/3

So the current in the circuit I=V/R is 100/(706 2/3) = 15/106 A
(I'm deliberately not trying to round the result)

The voltage drop over R₄ is V=I*R = 15/106 * 500 ≈ 70

So answer C would be my choice.

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Match the installation type to its description.
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Answer:

Following are the types of installation matched to its respective definitions.

<h3>Upgrade installation:</h3>

What you do when you have a computer with an existing operating system that needs to be upgraded.

This means that while working on a window when you get attracted by the update introduced recently and you upgrade your window accordingly.

For example: Updating a window from 8 to 10 or desired features.

<h3>Multiple boot installation:</h3>

What you do when you have several operating systems on one computer.

In this type of installation, a computer has different windows for different accounts. You can boot to the desired installed window by switching account.

<h3>Clean installation:</h3>

What you do on a brand new computer that has never been set up before and does not have an operating system on it yet.

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<h2>I hope it will help you!</h2>
5 0
3 years ago
A small company with 100 computers has hired you to install a local area network. All of the users perform functions like email,
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Answer:

Answer to the following question is as follows;

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Answer:

A. ampersand

Explanation:

7 0
3 years ago
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The answer is most likely A.


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A 4-bit left shift register is initially in the 0000 state, with all the flip flops storing 0s. A group of bits 1011 is serially
frutty [35]

Answer:

0010

Explanation:

Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:

Initial State of the Register:

0000

Group of bits entering:

1011

<u>First Clock Cycle:</u>

0000 <em>(This bold bit will move out)</em>

1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>

The resulting Sequence:

0001

<u>Second Clock Cycle:</u>

0001 <em>(This bold bit will move out)</em>

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The resulting Sequence:

0010 <em>(Final Answer)</em>

6 0
3 years ago
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