Answer:
The correct answer to this question is option (1).
Explanation:
Let x1 = Is number of pages that printer A can print in page/minute.
thus x1 + 5 = Is number of page that printer B can print in page/minute.
As printer A finishes his work in 60 min. So the task has 60x1 pages. As printers A and B both finish that task in 24 minutes. So the equation can be given as:
60x1 = 24x1 + 24(x1 + 5)
60x1 = 24x1 + 24x1 + 120
60x1=48x1 + 120
60x1-48x1=120
12x1=120
x1=120/12
x1=10
put the value of x1 in to (60x1). Therefore, the task has 60(10) = 600 pages. the task contains 600 pages.
So the answer to this question is option (1).
The correct answer that would best complete the given statement above would be the term addWindowListener. <span>The method needed to arrange for an object to be notified when a window's close-window button has been clicked is addWindowListener. Hope this is the answer that you are looking for. </span>
The Big Five Factors are: "Open, Agreeable, Stable, Conscientious, and Extraverted"
"Empathetic" is not one of the Big Five Factors.
<span>According to the Big Five Factors model, all but empathetic are categories.</span>
Answer:
a. 2^6, or 64 opcodes.
b. 2^5, or 32 registers.
c. 2^16, or 0 to 65536.
d. -32768 to 32768.
Explanation:
a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.
b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.
c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.
d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.