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Lelu [443]
3 years ago
6

15 Enter In simplest form. 18 15 = 18​

Mathematics
2 answers:
borishaifa [10]3 years ago
5 0

Answer:

The simplest form of 1518 is 56.

Step-by-step explanation:

charle [14.2K]3 years ago
4 0

Answer:

Didnt understand but if the question is

15/18

the answer is 56

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The table shows the balance of a money market account over time. Write a function that represents the balance y (in dollars) aft
dexar [7]

9514 1404 393

Answer:

  y = 2200(1.08^t)

Step-by-step explanation:

The interest earned the first year is ...

  (2376 -2200)/2200 = 0.08 = 8%

The balances the remaining years are consistent with that interest being compounded annually. An appropriate function is ...

  y = 2200(1.08^t)

_____

The compound interest formula is ...

  A = P(1 +r/n)^(nt) . . . . principal P earning rate r compounded n times per year for t years

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3 years ago
I have 2 questions:
Aneli [31]

The first answer is 48. The next answer is also 48.

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3 years ago
Letters a, b, c, and d are angle measures.
DerKrebs [107]
D
b equals to 75 because they are diagonal, and the one diagonal to a equals 105 so that a and b form a line.
In order to prove f||g, we need to prove c=b, so c equals 75, d equals 105
7 0
2 years ago
Read 2 more answers
Help me with number 9 please
Firdavs [7]
B'(-7,-5)
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6 0
3 years ago
The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
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