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ki77a [65]
3 years ago
15

Find the product of 8341 and 235

Mathematics
1 answer:
Fudgin [204]3 years ago
6 0

Answer:

1,960,135

Step-by-step explanation:

Product = ×

Mutiply your 2 numbers: 8341 × 235

Giving you: 1,960,135

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Serhud [2]

tell you teacher to Fu** off

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3 years ago
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Describe transformation given by (x,y) (x, y + 2)
Nadusha1986 [10]

Answer:

This graph has been translated. Translation is when the image on the graph has been shifted along one or both of the axis. In this case, the graph has been shifted up two units as shown by the operation of addition on the y-value. Remember that translations are rigid movements, so the new image will be congruent to the pre-image.

4 0
3 years ago
I need to figure out how many solutions does the system of equations below have.
Aleonysh [2.5K]

Answer:

The system has one solution.

Step-by-step explanation:

To find the number of solutions of the system, we equal both equations for y.

If we have ax = b, in which both a and b are different of 0, we have one solution.

If both a and b are 0, we have infinite solutions.

If a is 0 and b is not, there are no solutions.

y=6/7x-8 and y=7/9x+10/9

So

\frac{6x}{7} - 8 = \frac{7x}{9} + \frac{10}{9}

\frac{6x}{7} - \frac{7x}{9} = \frac{10}{9} + 8

\frac{54x - 49x}{63} = \frac{10}{9} + \frac{72}{9}

\frac{5x}{63} = \frac{82}{9}

45x = 63*82

Both a and b are different of 0, so the system has one solution.

6 0
3 years ago
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help
VMariaS [17]

Answer: a) 8.779 years

               b) 8.664 years

<u>Step-by-step explanation:</u>

a)

A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}

  • A: accumulated amount (balance)
  • P: principal amount (original/initial investment)
  • r: interest rate (convert to a decimal)
  • n: number of times compounded per year
  • t: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}

b)  

A=Pe^{rt}

1800=900e^{0.08t}\\\\\\2=e^{0.08t}\\\\\\ln\ 2=0.08t\\\\\\\dfrac{ln\ 2}{0.08}=t\\\\\\\large\boxed{8.664=t}

4 0
3 years ago
In the above figure, m∠A = 32° and m∠B = (2x + 14)°. If angles A and B are complementary angles, what are the value of x and the
Neko [114]

Complementary angles have a sum of 90

32+2x+14=90

2x+46=90

2x=44

x=22 the second angle is 58

2(22)+14=58

5 0
3 years ago
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