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NISA [10]
3 years ago
12

What is the answer to this? What are the 2 equations for this?

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

Answer:

140-100 i don't know the other one

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Help pls i need help !!
Ivanshal [37]

Answer:

Ray, Line, Transversal?, Plane, Segment

Step-by-step explanation:

6 0
3 years ago
Find the solution set for this equation.<br> a2 + a=0<br> Separate the two values with a comma.
ira [324]

Answer:

a = 0,-1

Step-by-step explanation:

a^2 + a=0

Factor out an a

a(a+1) =0

Using the zero product property

a=0   a+1 =0

a=0  a= -1

6 0
3 years ago
Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
7 0
3 years ago
200 = 16(6t − 3) solve this and show the work please
amm1812

Answer:

t = 2.58333

Step-by-step explanation:

use the distributive property:

200 = 16(6t - 3)

multiply the 16 to each value in the parenthesis:

200 = 96t - 48

now add 48 to both sides:

200 = 96t - 48

+48            + 48

248 = 96t

now divide each side by 96:

248/96 = 96t/96

t = 2.583333

decimal form: 2.5833333

mixed number: 2\frac{7}{12}

5 0
2 years ago
Given the sample triangle below and the conditions , find the hypotenuse of the triangle
alukav5142 [94]
<span>ind the square root of c2.</span><span> Use the square root function on your calculator (or your memory of the multiplication table) to find the square root of c</span>2. The answer is the length of your hypotenuse!<span>In our example, <span>c2 = 25</span>. The square root of 25 is 5 (5 x 5 = 25, so Sqrt(25) = 5). That means c = 5, the length of our hypotenuse!</span> The Pythagorean Theorem describes the relationship between the sides of a right triangle.<span> It states that for any right triangle with sides of length a and b, and hypotenuse of length c, </span><span>a2 + b2 = c2


</span>Make sure that your triangle is a right triangle.<span> The Pythagorean Theorem only works on right triangles, and by definition only right triangles can have a hypotenuse. If your triangle contains one angle that is exactly 90 degrees, it is a right triangle and you can proceed.</span><span>Right angles are often notated in textbooks and on tests with a small square in the corner of the angle. This special mark means "90 degrees."
</span><span>

</span>Assign variables a, b, and c to the sides of your triangle.<span> The variable "c" will always be assigned to the hypotenuse, or longest side. Choose one of the other sides to be </span>a,<span> and call the other side </span>b<span> (it doesn't matter which is which; the math will turn out the same). Then copy the lengths of a and b into the formula, according to the following example:</span><span>If your triangle has sides of 3 and 4, and you have assigned letters to those sides such that a = 3 and b = 4, then you should write your equation out as: <span>32 + 42 = c2</span>.
</span>
Find the squares of a and b.<span> To find the square of a number, you simply multiply the number by itself, so </span><span>a2 = a x a</span>. Find the squares of both a and b, and write them into your formula.<span><span>If a = 3, a2 = 3 x 3, or 9. If b = 4, then b2 = 4 x 4, or 16.</span><span>When you plug those values into your equation, it should now look like this: <span>9 + 16 = c2</span>.
</span></span>


<span>Add together the values of <span>a2</span> and <span>b2</span>.</span><span> Enter this into your equation, and this will give you the value for c</span>2. There is only one step left to go, and you will have that hypotenuse solved!<span>In our example, 9 + 16 = 25, so you should write down <span>25 = c2</span>.

</span>
6 0
3 years ago
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