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4 years ago

Solve. x^-9 y^3 / x^-7 y^8

1 answer:

3 0

$\dfrac{x^{-9}y^3}{x^{-7}y^8}=x^{-9-(-7)}y^{3-8}=x^{-2}y^{-5}=\dfrac{1}{x^2y^5}\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}$

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Simplify the expression (2-5i)-(4-4i)

RUDIKE [14]

(2 - 5i) - (4 - 4i)
-2 - i is your answer. Hope it helps! :) If you could vote my answer as the brainiest, that would be awesome! :)

3 0

3 years ago

PLEASE HELP! can anyone who answers this provide explanations and how to solve each and as well? ;-;

sergeinik [125]

Answer:

1) 6.32

2)8.66

3)5.74

4)9.49

5)16.55

6)21.21

7)25.98

Step-by-step explanation:

1) 6,7

2) 8,9

3) 5,6

4) 9,10

5) 16,17

6) 21,22

7) 25,26

8 0

4 years ago

3) Find the equation of a line perpendicular to y = -3x + 7 that goes through the point (-1, 2)

Alchen [17]

Step-by-step explanation:

In order to find the new equation I used the following formula :

y - y1 = m (x -x1)

* x1 & y1 are the coordinates of the given point

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

6 0

3 years ago

Is it mathematically correct to say that:

Step2247 [10]

Answer: Yes

Step-by-step explanation:

Since the numerator is multiplying square root 13 by square root 2, we can break them apart.

$\displaystyle \frac{\sqrt{13*2}}{\sqrt{13}} =\frac{\sqrt{13}*\sqrt{2} }{\sqrt{13}}$

You are correct, $\sqrt{13}$ over $\sqrt{13}$ is equal to one, so we can "cancel them out" of our expression.

$\displaystyle \frac{\sqrt{13} }{\sqrt{13}} = 1$

This leaves us with: $\sqrt{2}$

We can also test this by using a calculator:

$\frac{\sqrt{13*2}}{\sqrt{13}} \approx 1.41421356\\\sqrt{2} \approx 1.41421356\\1.41421356=1.41421356$

8 0

2 years ago

Pleaseee help i need it asap

Simora [160]

She will win because she's black lol

5 0

3 years ago