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Ludmilka [50]
3 years ago
11

Solve. x^-9 y^3 / x^-7 y^8

Mathematics
1 answer:
aniked [119]3 years ago
3 0

\dfrac{x^{-9}y^3}{x^{-7}y^8}=x^{-9-(-7)}y^{3-8}=x^{-2}y^{-5}=\dfrac{1}{x^2y^5}\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}

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