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Alex
2 years ago
12

Evaluate the expression for x= 9 5x + 3

Mathematics
2 answers:
Vesna [10]2 years ago
6 0
48


(5)(9) + 3
45 + 3


Hope this helps!!!!
butalik [34]2 years ago
3 0

Answer:The answer is 48

Step-by-step explanation: 9 x 5 = 45 + 3= 48

You might be interested in
If 2x<br> + 13x – 7 = 0, then x could equal to which of the following?
Leokris [45]

Answer:

7 / 15

Step-by-step explanation:

15x - 7 = 0

15x = 7

x = 7/15

7 0
3 years ago
Read 2 more answers
I really need help with these questions, i don’t even have a clue how to do these.
Anuta_ua [19.1K]

Answer:

231

Step-by-step explanation:

because the whole circle has an area of 360 so on the right side there is half and a little more so you would cut it in half so you have 180 and on the right side you still have a little left so thats about 10 so now you have 190 then you add 21 +20 you have 41 +190 =231 hope this helps

3 0
2 years ago
Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. F(x) =
Troyanec [42]

Answer:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Step-by-step explanation:

Given:

The cdf is as follows:

                           F(x) = 0                  x < 0

                           F(x) = (x^2 / 25)     0 < x < 5

                           F(x) = 1                   x > 5

Find:

(a) Calculate P(X ≤ 3).

(b) Calculate P(2.5 ≤ X ≤ 3).

(c) Calculate P(X > 3.5).

(d) What is the median checkout duration ? [solve 0.5 = F()].

(e) Obtain the density function f(x). f(x) = F '(x) =

(f) Calculate E(X).

(g) Calculate V(X) and σx. V(X) = σx =

(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].

Solution:

a) Evaluate the cdf given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

     P (x <= 3 ) = (3^2 / 25)  - 0

     P (x <= 3 ) = 0.36

b) Evaluate the cdf given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

     P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

     P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the cdf given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

     P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

So, P( x < a ) = 0.5

      (x^2 / 25) = 0.5

       x^2 = 12.5

      x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

       pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

         E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

         E(X) = integral ( x^2 / 12.5)    

         E(X) = x^3 / 37.5                    limits: 0 to 5

         E(X) = 5^3 / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

         Var(X) = integral ( x^2 . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

         Var(X) = integral ( x^3 / 12.5).dx - (E(X))^2    

         Var(X) = x^4 / 50 | - (3.3333)^2                         limits: 0 to 5

         Var(X) = 5^4 / 50 - (3.3333)^2 = 13.8891

         s.d(X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

          h(x) = (f(x))^2 = x^2 / 156.25

  The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

         E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

         E(h(X))) = integral ( x^3 / 156.25)    

         E(h(X))) = x^4 / 156.25                       limits: 0 to 25

         E(h(X))) = 25^4 / 156.25 = 2500

8 0
3 years ago
Could you pleaseee help me
vladimir1956 [14]
3.6 \times 10^{14} \times 8 \times 10^{10}

= 3.6 \times 8 \times 10^{14 + 10}

= 28.8  \times 10^{24}

= 2.88  \times 10^{25}

3 0
3 years ago
Make a down payment of $1500 and finance the rest of $20000 at 1.9% interest rate, making equal monthly payments for 5 years.
Rudik [331]
We know that we have to m<span>ake a down payment of $1500 and finance the rest of $20000 at a 1.9% interest rate, making equal monthly payments for 5 years. Our first step to solve this problem would be to convert 5 years into months. 

1 year = 12 months 

12 * 5 = 60 months 

Therefore, in 5 years there are 60 months. 

Now lets solve this problem step by step. 

Subtract the down payment from $20,000

</span>$20000-$1500=$18500

Multiply the remaining number by the interest rate. 

$18500 *1.9 = $35150 

Divide 35150 by number of months in 5 years (60)

$35150 / 60 = $585 

<span>Therefore, you have to pay $585 per month. </span>
7 0
3 years ago
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