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3 years ago

Please help find the perimeter

Mathematics

1 answer:

Usimov [2.4K]3 years ago

4 0

Answer:

Perimeter of the given figure = 28 units

Step-by-step explanation:

Perimeter of the given figure = Length of AB + Length of BC + Length of CD + Length of DE + Length of EF + Length of FG + Length of GH + Length of AH

Length of AB = 4.5 units

Length of BC = 2 units

Length of CD = 2 units

Length of DE = 4 units

Length of EF = 5.5 units

Length of FG = 1.5 units

Length of HG = 1 units

Length of AH = 7.5 units

Perimeter of ABCDEFGH = 4.5 + 2 + 2 + 4 + 5.5 + 1.5 + 1 + 7.5

= 28 units

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Consider the statement "For all real numbers r, if r 2 is irrational then r is irrational." a. Write what you would suppose and

d1i1m1o1n [39]

Answer:

a. r is rational; r² is rational

b. r is rational; r² is rational

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3 years ago

The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f

TEA [102]

According to the graph, we have for $0$

$f'(x)=\begin{cases}x&\text{for }0$

$f'$ is positive for all $0$ , which means $f$ is strictly increasing on the interval [0, 5], and so its minimum value on this interval occurs at $x=0$ .

We can integrate $f'$ along each subinterval above to find $f$ :

$f(x)=\begin{cases}\dfrac{x^2}2+C_1&\text{for }0\le x\le 2\\\\2x+C_2&\text{for }2\le x\le 4\\\\10x-x^2+C_3&\text{for }4\le x\le5\end{cases}$

$f'$ is continuous, which means $f$ is also continuous. This means

$\displaystyle\lim_{x\to2}\left(\dfrac{x^2}2+C_1\right)=\lim_{x\to2}(2x+C_2)$

$\implies2+C_1=4+C_2\implies C_1=2+C_2$

and

$\displaystyle\lim_{x\to4}(2x+C_2)=\lim_{x\to4}(10x-x^2+C_3)$

$\implies8+C_2=24+C_3\implies C_2=16+C_3$

Given that $f(5)=10$ , we have

$10(5)-5^2+C_3=10\implies C_3=-15\implies C_2=1\implies C_1=3$

so that over $0\le x\le 2$ we have $f(x)=\dfrac{x^2}2+3$ . We know the minimum value occurs at $x=0$ , so it is 3 and the answer is A.

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3 years ago

Change 11 5/8 to a improper fraction

TiliK225 [7]

Simple,

You have 11 $\frac{5}{8}$

to change it into an improper fraction multiply the whole number (11) by the denominator (8)

11*8=88

Then, add the numerator to what you have multiplied..

88+5=93

Finally, use the original denominator....

Making your answer...

$\frac{93}{8}$

Thus, your answer.

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3 years ago

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Answer:

$\frac{1}{7}$

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