Question

10 POINTS

Answer 1

Answer:

C, F, D

Step-by-step explanation:

For each side of each triangle, think of the side as the hypotenuse of a right triangle. Then use the Pythagorean theorem to find the length of the hypotenuse, which is the side of the triangle.

Left problem:

From point C to point A, go 2 left and 7 up.

$AC = \sqrt{2^2 + 7^2} = 7.3$

From point A to point B, go 5 right and 1 down.

$AB = \sqrt{5^2 + 1^2} = 5.1$

From point B to point C, go 6 down and 3 left.

$BC = \sqrt{6^2 + 3^2} = 6.7$

Perimeter = 7.3 + 5.1 + 6.7 = 19.1

Do the same for the other triangles.

Middle problem:

From point F to point D, go 2 left and 7 up.

$FD = \sqrt{2^2 + 7^2} = 7.3$

From point D to point E, go 7 right and 2 down.

$DE = \sqrt{7^2 + 2^2} = 7.3$

From point E to point F, go 5 down and 5 left.

$EF = \sqrt{5^2 + 5^2} = 7.1$

Perimeter = 7.3 + 7.3 + 7.1 = 21.7

Right problem:

From point L to point J, go 7 left and 1 up.

$LJ = \sqrt{7^2 + 1^2} = 7.1$

From point J to point K, go 4 up and 5 right.

$JK = \sqrt{4^2 + 5^2} = 6.4$

From point K to point L, go 2 right and 5 down.

$KL = \sqrt{2^2 + 5^2} = 5.4$

Perimeter = 7.1 + 6.4 + 5.4 = 18.9