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2 years ago

10x²-17x+3 (factor this polynomial in a 3x3 table form) picture please

Mathematics

2 answers:

Ymorist [56]2 years ago

3 0

(2x-3)(5x-1). I Think that is the answer.

Aleks [24]2 years ago

3 0

Hey TheLearner2,

Lets solve your polynomial together.

To find the solution we have to factor, so let's solve this step by step.

The Polynomial is : $10x^2-17x+3$

The first step is to break the expression into groups.

⇒ $\left(10x^2-2x\right)+\left(-15x+3\right)$

Now we have to factor the expression

⇒ $2x\left(5x-1\right)-3\left(5x-1\right)$

Now we factor the common term: $\left(5x-1\right)$

⇒ $\left(5x-1\right)\left(2x-3\right)$

Hope this helps,

AnthrαX

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Y_Kistochka [10]

Answer:

Step-by-step explanation:

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2 years ago

A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The

Oksanka [162]

Answer:

a) $[-0.134,0.034]$

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

$s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}$ ,

where $n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19$ .

The mean difference $\mu_1 - \mu_2 = 10.85 - 10.90 = -0.05$ .

The confidence interval is

$(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}$

$= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]$

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0

3 years ago

Find the solution set of the absolute value equation: |2x−6|+4=20

vekshin1

$|2x - 6| = 16 \\ 2x - 6 = 16 > > > x = \frac{22}{2} = 11 \\ 2x - 6 = - 16 > > x = - 5$

6 0

2 years ago

Pablo's retirement party will cost $8 if he invites 4 guests. If there are 6 guests, how

mezya [45]

Answer:

$12

Step-by-step explanation:

Step 1:

$8 : 4 = x : 6

Step 2:

4x = 48

Answer:

x = 12

Hope This Helps :)

6 0

3 years ago

Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?

Eddi Din [679]

Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

$|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }$

The magnitude of vecor v is given to be 10. So we can write:

$10= \sqrt{ (-1-x)^{2} + (5-y)^{2} } \\ \\ 100=(-1-x)^{2} + (5-y)^{2}$

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.

The point in option d, satisfies the equation.

$100=(-1+7)^{2} +(5+3)^{2} \\ \\ 
100=36+64 \\ \\ 
100=100$

Thus, the answer to this question is option D

7 0

2 years ago