Step-by-step explanation:
Area of a trapezium = SOPS/2 × ph
Sops is the sum of 4+10 = <u>1</u><u>4</u>
14/2 is 7. 7×4 = <u>2</u><u>8</u>
<u>A</u><u> </u><u>=</u><u> </u><u>2</u><u>8</u><u>c</u><u>m</u><u>²</u>
Area = L×W
10×6= 60cm²
Answer:
90
Step-by-step explanation:
You need to simply add all the given numbers together and enter the missing number that'll make the total 0. So:
-75 + (-25) = -100
-100 + 10 = -90
-90 + <u>90</u> = 0
Thus, adding a 90 in the empty box will make it 0.
Answer:
x=12
Triangle abc and Def are congruent but different sizes. The original triangle has side values of 2, 6 and 5. Then the shape is dilated by an unknown factor, giving it the side lengths of 4, x, and 10. Looking at the increase in side lengths we see that theres an increase of 2 to 4, or multiplying by 2 and an increase from 5 to 10, or multiplying by to. So now that we know there was a dilation of 2, we multiply 6 by 2 to find 12
Answer:
(-2 , 2)
Step-by-step explanation:
A(-8 , 2) = (x1 , y1)
B(4 , -2) = (x2 , y2)
midpoint = (x1 + x2/2 , y1 + y2/2)
=(-8 + 4/2 , 2-(-2)/2)
=(-4/2 , 2+2/2)
(-2 , 2)
(3 , 7) = (x1 , y1)
(9 , 2) = (x2 , y2)
distance of PQ = 
=
=
=
=
=7.8 unit
Answer:
<h3>See explanations below</h3>
Step-by-step explanation:
1) Given the recursive function An=an-1 + 3 when a1 = 5, we are to find the first four terms;
First term a1 = 5
a2 = a1 +3
a2 = 5 + 3
a2 = 8
a3 = a2 + 3
a3 = 8+3
a3 = 11
a4 = a3 + 3
a4 = 11 + 3
a4 = 14
<em>The first four terms are 5, 8, 11 and 14</em>
<em></em>
<em>2) </em>For the recursive function An=an-1 + 2/3 when a1 = 1
a2 = a1 + 2/3
a2 = 1 + 2/3
a2 = 5/3
a3 = a2 + 2/3
a3 = 5/3 + 2/3
a3 = 7/3
a4 = a3 + 2/3
a4 = 7/3 + 2/3
a4 = 9/3
a4 = 3
<em>Hence the first four terms of the sequence are 2/3, 5/3, 7/3, 3</em>
<em></em>
3) For the recursive function An=an-1 + 12 when a1=30
a2 = a1 + 12
a2 = 30 + 12
a2 = 42
a3 = a2 +12
a3 = 42 + 12
a3 = 54
a4 = a3 + 12
a4 = 54+12
a4 = 66
<em>Hence the first four terms of the sequence are 30, 42, 54, 66</em>
