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3 years ago

11

For each 70 mm of coloured fabric Alex uses to make his curtains, he also uses 20 cm of white fabric. Express the amount of whit

e fabric to coloured fabric as a ratio in its simplest form.

1 answer:

Inessa05 [86]3 years ago

6 0

Here is the answer. First change 20cm in mm = 200mm
ratio = 70mm/200
= 7 : 20
Hope this helps! Mark brainly please!

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A total of $12,000 is invested at an annual interest rate of 9%. Find the balance

sineoko [7]

Answer:

$18,726.11

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First lets change 9% into a decimal:

9% -> $\frac{9}{100}$ -> 0.09

Since the interest is compounded quarterly, we will use 4 for n. Lets plug in the values now:

$A=12,000(1+\frac{0.09}{4})^{4(5)}$

$A=18,726.11$

<u>The balance after 5 years is $18,726.11</u>

6 0

3 years ago

I NEED ANSWERS ASAP(WORTH 20 POINTS) WILL MARK BRAINLIEST

eimsori [14]

Answer:

B. (negative infinity, -1)

3 0

3 years ago

Read 2 more answers

An electronics store received two shipments of radios. Of the 250 radios in the first shipment, exactly 6% were damaged. In the

nataly862011 [7]

Answer:

Total number of not damaged = 451

C. 451

Step-by-step explanation:

In the first shipment, 6% of the 250 radios where damaged.

Number of damaged= 6/100 * 250

Number of damaged= 6*2.5

Number of damaged= 15 radios.

Number of not damaged= 250-15

Number of not damaged = 235 radios

In the second shipment, 4% of the radios were damaged

Let the number of second shipment= y

0.04 of y where damaged

Total number of radio damaged= 24

15 + 0.04y = 24

0.04y= 24-15

0.04y = 9

Y= 9/0.04

Y= 225

Number of radio in the second shipment= 225

Number of damaged in the second shipment= 0.04*225

Number of damaged in the second shipment= 9

Number of not damaged in the second shipment= 225-9

Number of damaged in the second shipment= 216

Total number of not damaged

= 235+216

= 451

Total number of not damaged= 451

7 0

3 years ago

Need help with 7-10 please and thank you!!

Archy [21]

Answer:

#7: MK, LS and PR

#8: PN and PQ

#9: no

#10: no

Step-by-step explanation:

#7: lines MK, LS and PR are not intersecting each other, so these lines are parallel each other

#8: between lines PN and PQ is an right angle, so the lines PN and PQ are perpendicular

#9: lines PN and KM have an intesecting point, so they're not parallel

#10: there is no right angle between lines PR and NP

3 0

3 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

4 years ago