Ask question

Ask question

All categories

Naddika [18.5K]

3 years ago

8

A storage pod has a rectangular floor that measures 21 feet by 9 feet and a flat ceiling that is 7 feet above the floor. Find th

e area of the floor and the volume of the pod.

1 answer:

mario62 [17]3 years ago

4 0

Answer:

area: 189 ft²
volume: 1323 ft³

Step-by-step explanation:

The area of the rectangular floor is the product of its length and width:

A = LW = (21 ft)(9 ft) = 189 ft²

The volume of the pod is the product of that floor area and the height:

V = Bh = (189 ft²)(7 ft) = 1323 ft³

The area of the floor is 189 ft²; the volume of the pod is 1323 ft³.

You might be interested in

Plz help I put 26 on the points plz help

alex41 [277]

Answer:

do you need help with the L and P???????

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which equation represents the hyperbola in general form?

valina [46]

ANSWER

D.

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

EXPLANATION

The standard equation of the hyperbola is

$\frac{ {(y - 2)}^{2} }{4} - \frac{ {(x - 2)}^{2} }{9} = 1$

We multiply through by 36 to obtain:

$9 {(y - 2)}^{2} - 4( {x - 2)}^{2} = 36$

We now expand to get,

$9( {y}^{2} - 4y + 4) - 4( {x}^{2} - 4x + 4) = 36$

Expand :

$9 {y}^{2} - 36y + 36 - 4 {x}^{2} + 16x - 16 = 36$

To get the general form, we equate everything to zero to get,

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

The correct choice is D.

7 0

3 years ago

Help me solve this please

Semenov [28]

$\huge\underline{ \underline{ \bf{Answer࿐} }}$

parallel sides measure :

10 ft -(a)
12 ft. -(b)

Area :

44 ft²

height (h) = x

___________________

$\boxed{Area = \frac{1}{2} \times (a + b) \times h}$

$\dfrac{1}{2} \times (10 + 12) \times x = 44$

$\dfrac{1}{2} \times 22 \times x = 44$

$11x = 44$

$\boxed{ 4 \: \: ft}$

Therefore, height of Trapezoid is 4 ft

_____________________________

$\mathrm{ \#TeeNForeveR}$

5 0

3 years ago

John has a rectangular-shaped field whose length is 62.5 yards and width is 45.3 yards. The area of the field is ________ square

oee [108]

Area = 2831.25 square yards

Perimeter =215.6 yards

EXPLANATION

The area and perimeter of a rectangular field are found using the formula for finding the area and perimeter of a rectangle respectively.

That means, area of the rectangular field is given by the formula,

$A= l\times w$

We just have to substitute
$l=62.5$ and $w= 45.3$ into the given formula and evaluate.

This implies that;

$A= 62.5\times 45.3$

This gives the area of the rectangular-shaped field to be;

$A= 2831.25$ square yards.

Now for the perimeter, we use the formula

$P=2w +2l$

Or

$P=2(w +l)$

Substituting the values for the length and width gives,

$P=2(62.5+45.3)$

$\Rightarrow P=2(107.8)$

$\Rightarrow P=215.6$

Hence the perimeter of the rectangular shaped field is 215.6 yards.

8 0

3 years ago

The length of a rectangle is 3 times the length of a

laila [671]

$larger\ rectangles:3l\ \times\ w\\\\smaller\ rectangles:l\ \times\ w\\\\A_{larger}=kA=3lw\\\\A_{smaller}=A=lw\\\\\frac{A_{larger}}{A_{smaller}}=\frac{kA}{A}=k\\\\k=\frac{3lw}{lw}=3\\\\Answer:J.$

4 0

3 years ago