We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
HD = 10.5
Step-by-step explanation:
Given BH = 3, GH = 2, BF = 10
Step 1: To find HF:
HF = BF – BH
HF = 10 – 3
HF = 7
Step 2: To find HD:
We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.
⇒ GH × HD = BH × HF
⇒ 2 × HD = 3 × 7
⇒ HD = 10.5
Hence, the value of HD = 10.5.
Answer:
12$ an hour
Step-by-step explanation:
60 minutes in an hour 15 times 4= 60 which is one hour, so 4 times 3 equals 12 which is the answer
40,000 is 10 times as much as 4,000
Answer:
y = x + 5
Step-by-step explanation:
The graph of the ramp function y = x is a straight line with slope +1 and passing through the origin. If the whole graph is shifted up 5 units, the equation/function becomes
y = x + 5. The resulting graph is parallel to y = x.
