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snow_tiger [21]
3 years ago
5

A segment has endpoints at (15,-11) and (42,-11).How many units long is the segment?

Mathematics
2 answers:
vfiekz [6]3 years ago
6 0
Id say the answer is D i might be wrong tho
Goshia [24]3 years ago
5 0
Hey there,

You have to use this formula : 

D= \sqrt{( x_{2} -  x_{1})^2 + ( y_{2} - y_{1} )^2  }
D=  \sqrt{(  42 - 15  )^2+(  -11 + 11  )^2
D=  27

Therefore, the answer would be the option B.

Hope this helps !

Photon
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The height of a ball thrown vertically upward from a rooftop is modelled by h(t)= -4.8t^2 + 19.9t +55.3 where h (t) is the balls
nikitadnepr [17]

By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.

<h3>How to determine the maximum height of the ball</h3>

Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:

- 4.8 · t² + 19.9 · t + (55.3 - h) = 0

The height of the ball is a maximum when the discriminant is equal to zero:

19.9² - 4 · (- 4.8) · (55.3 - h) = 0

396.01 + 19.2 · (55.3 - h) = 0

19.2 · (55.3 - h) = -396.01

55.3 - h = -20.626

h = 55.3 + 20.626

h = 75.926 m

By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.

To learn more on quadratic equations: brainly.com/question/17177510

#SPJ1

6 0
2 years ago
HELPS ME I NEEEEEEEED THE ANSWER TO THIS
Svetlanka [38]
The answer I believe is 5.8
6 0
3 years ago
Read 2 more answers
Which expression represents a factorization of 16a - 24ab
Marizza181 [45]

I would choose A

You can simply try every answer and see which one gives you 16a-24ab

4 0
3 years ago
In which quadrant is the orderd pair (2,-5)​
OverLord2011 [107]

Answer:

4

(+, -) coordinates

4 0
3 years ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

8 0
1 year ago
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