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PtichkaEL [24]
3 years ago
8

SOMEONE PLSS HELP I REALLY NEED THIS I'LL GIVE BRAILIEST!! SHOW WORK PLS ONLY NUMBER 5 AND 7 THANKK UU

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

u forgot to put the picture...

Step-by-step explanation:

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3 one is the answer I think
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Find the given angle to the nearest degree.
Darina [25.2K]

Answer:

\alpha=44\°

Step-by-step explanation:

By definition, the tangent of an angle is the quotient between the side opposite the angle and the side adjacent to the angle

In other words:

tan(\alpha) = \frac{opposite}{adjacent}

In this triangle, the length of the side adjacent to the desired angle is 50, and the length of the opposite side is 48

So:

tan(\alpha) = \frac{48}{50}\\\\tan(\alpha)= 0.96

Finally

\alpha =arctan(0.96)\\\\\alpha=44\°

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3 years ago
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A train travels at 45 miles per hour. Write and equation that represents the distance, d, that the train will travel, in t hours
jek_recluse [69]

Answer:

d = 45 * t

Step-by-step explanation:

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d = 45 * t

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3 years ago
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Name all the radii.<br><br> Please help me.
rosijanka [135]

Answer:


Step-by-step explanation:

we know,

radius is the distance from center of a circle to the circumference.

Here, from the figure we get,

There are three radius marked in this circle.

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OU , OR and OT


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7 0
4 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

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3 years ago
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