Given :
A squirrel climbs up a tree. She starts at 0.5 feet up the tree, then climbs at a steady pace for 7.5 seconds.
She ends 4 feet up the tree.
Solution :
Now, distance covered is :
d = 4 - 0.5 = 3.5 feet.
Time taken, t = 7.5 seconds.
Distance climbed per second is :

Therefore, distance climber per second is 0.467 feet.
Hence, this is the required solution.
7 and 1/8. all you need to do is add these together by getting a common denominator of eight
Answer:
<h2>6x-3y=15</h2>
Solve for y.
y= −5+2x
Rewrite in slope-intercept form.
y=2x−5
Use the slope-intercept form to find the slope and y-intercept.
Slope: 2
y-intercept: (0,−5)
Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y values.
x y
0 −5
5/2 0
Graph the line using the slope and the y-intercept, or the points.
Slope: 2
y-intercept: (0,−5)
x y
0 −5
5/2 0
Step-by-step explanation:
Hope it is helpful....
Answer:
the rate of each train is 139 km/h and 159 km/h.
Step-by-step explanation:
let
v = the rate of the slower train
v + 20 = the rate of the faster train
d = 1490 km the distance that the two train will travel
t = 5 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v+20)t = d
5v + 5(v + 20) = 1490
5v+5(v+20)=1490
Step 1: Simplify both sides of the equation.
5v+5(v+20)=1490
5v+(5)(v)+(5)(20)=1490(Distribute)
5v+5v+100=1490
(5v+5v)+(100)=1490(Combine Like Terms)
10v+100=1490
10v+100=1490
Step 2: Subtract 100 from both sides.
10v+100−100=1490−100
10v=1390
Step 3: Divide both sides by 10.
10v/10 = 1390/10
v = 139km/h
Next
we add 139 to 20
139 + 20 = 159 km/h
the rate of each train is 139 km/h and 159 km/h.