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sergejj [24]
3 years ago
13

A relative frequency table is made from data in a frequency table. What is the value of g in the relative frequency table? Round

the answer to the nearest percent. 25% 33% 63% 68%

Mathematics
1 answer:
Paraphin [41]3 years ago
7 0

I've attached the image of this question.

Answer:

g = 33%

Step-by-step explanation:

To solve this;

The values in the ends of the rows are found by adding together the two previous cells.

Thus;

For the first row, we would add the value in cell AC to the value in AD to get the value in the corresponding column named "Total".  This means we add 20% +g to get 53%;

Thus;

20% + g = 53%

Subtract 20% from each side to give;

g = 53% - 20%

g = 33%

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Step-by-step explanation:

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Which graph shows the line y=35x−3?
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Given I=prt,where I=4.5,p =500,and t=2.5,what is r as a percent?
KIM [24]
PLUG in the numbers 
4.5=500 x R x 2.5
divide both sides by 500
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In percent you have to multiply by 100 which is 0.36%
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2 years ago
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A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a day waiting period to purchase
il63 [147K]

Answer:

The  90% confidence interval for the difference between proportions is (-0.260, -0.165).

Step-by-step explanation:

<em>The question is incomplete. The complete question is:</em>

<em>"A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that </em><em>318 of the 520 men </em><em>who were surveyed supported this proposed law while </em><em>379 of the 460 women </em><em>sampled said ‘‘yes”. Use this information to find a </em><em>90% confidence interval</em><em> for the difference in the two proportions, </em><em>pm - pw.</em><em> </em><em>Subscript pm</em><em> is the proportion of men who support the proposed law and </em><em>pw</em><em> is the proportion of women who support the proposed law. (Round answers to 3 decimal places.)"</em>

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample of men, of size nm=-0.26 has a proportion of pm=0.612.

p_m=X_m/n_m=318/520=0.612

The sample 2, of size nw= has a proportion of pw=0.824.

p_w=X_w/n_w=379/460=0.824

The difference between proportions is (pm-pw)=-0.212.

p_d=p_m-p_w=0.612-0.824=-0.212

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_m+X_w}{n_m+n_w}=\dfrac{318+379}{520+460}=\dfrac{697}{980}=0.711

The estimated standard error of the difference between means is computed using the formula:

s_{pm-pw}=\sqrt{\dfrac{p(1-p)}{n_m}+\dfrac{p(1-p)}{n_w}}=\sqrt{\dfrac{0.711*0.289}{520}+\dfrac{0.711*0.289}{460}}\\\\\\s_{pm-pw}=\sqrt{0.00039+0.00045}=\sqrt{0.001}=0.029

Then, the margin of error is:

MOE=z \cdot s_{pm-pw}=1.645\cdot 0.029=0.0477

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.212-0.0477=-0.260\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.212+0.0477=-0.165

The  90% confidence interval for the difference between proportions is (-0.260, -0.165).

6 0
3 years ago
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