Answer:
Step-by-step explanation:
Hello,
![2(x+3)^2-10\\=2[(x+3)^2-5]\\=2[(x+3)^2-(\sqrt{5})^2]\\\\=2[(x+3+\sqrt{5})(x+3-\sqrt{5})]](https://tex.z-dn.net/?f=2%28x%2B3%29%5E2-10%5C%5C%3D2%5B%28x%2B3%29%5E2-5%5D%5C%5C%3D2%5B%28x%2B3%29%5E2-%28%5Csqrt%7B5%7D%29%5E2%5D%5C%5C%5C%5C%3D2%5B%28x%2B3%2B%5Csqrt%7B5%7D%29%28x%2B3-%5Csqrt%7B5%7D%29%5D)
Hope this helps
Answer:
it is true. any whole number has a 0 following the decimal
Answer:
s a vertex is a corner so s
To do this, we just have to add as if we were adding regular numbers. 3p+5p= 8p. To add the next p, we have to pretend that there is a one right in front of it. Indeed, there is a one in front of the p, but most people and most math problems don't put the one there. But anyways, 8p+1p=9p. Your answer is 9p.
Since the 4 sides of the square are equal, divide the perimeter by 4 to get one side.
100/4 = 25 cm
