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3 years ago

What it 40x + 24? I can't figure this out.

Mathematics

1 answer:

Dmitrij [34]3 years ago

7 0

8(5x+3)

If you miltiplied 8 x 5x it will give you 40 x

And 8 x 3 is 24

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Solve for x and y 2x+3yi=-14+9i

ryzh [129]

2,314 is the anwser

4 0

4 years ago

^Answer needed ASAP! Solve x2-6x=-5 by completing the square. show ALL work

ankoles [38]

Have a nice day, be safe and healthy :)

Hope this helped

formula:

(a+b)^2

= a^2+2ab+b^2

Here, we have x^2 (as in a^2)

and -6x (as in 2ab), which, we're missing the b^2

(I'm not really sure how to describe this but bare with me)

-6/2 (-6 is from the -6x) = -3 (the b)

-3^2 = -3*-3 which is equal to 9 (positive 9)

Writing it out -

x^2-6x+9 = -5

- Addition of inequality -

Since we add 9 to the left side, we have to add 9 to the right side; which gives us:

x^2-6x+9=4

Next, lets put the x^2-6x+9 as in (a+b)^2:

(x-3)^2 = 4

Then let's do the square root of equality (square rooting both sides) :

x-3 = 2

Finally lets add 3 to both sides

x = 5

THE ANSWER IS x=5

Have a nice day, be safe + healthy - Hope this helped

8 0

4 years ago

PLEASE HELP!!! ILL GIVE BRAINLIEST !!

ioda

Answer:

4532

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

NO SOLUTION

7 0

3 years ago

Could anyone give me the answer to this question?

love history [14]

Answer:

Step-by-step explanation:

$\angle AOC$ is made up of s + r, and since r is $\frac{3}{5}$ of $\angle AOC$ we know r must be the remaining $\frac{2}{5}$ of $\angle AOC$ .

We can solve for $\angle AOC$ by using this equation:

$\frac{2}{5}\angle AOC = 24\\(\frac{2}{5}\angle AOC)\frac{5}{2} = (24)\frac{5}{2}\\ \boxed{\angle AOC = 60}$

1. 2 fifths of $\angle AOC$ is 24

2. multiply both sides by $\frac{5}{2}$ to isolate $\angle AOC$

3. $\angle AOC$ is 60°

We can now solve for r

$r = \frac{3}{5}\angle AOC\\r = \frac{3}{5}(60)\\\boxed{r = 36}$

1. the equation the problem gave us

2. substitute $\angle AOC$ for 60 (we solved for it before)

3. $r$ is 36°

4 0

3 years ago