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kobusy [5.1K]
3 years ago
8

Find the slope of (6,2) (8,4)

Mathematics
1 answer:
denis23 [38]3 years ago
4 0

Answer:

2/2 = 1

Step-by-step explanation:

y2 - y1           4 - 2          2            Equals 1

x2 - x1           8 - 6          2

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If y varies directly as x, and y is 12 when x is 1.2, what is the constant of variation for this relation? A) 1 B) 10 C) 10.8 D)
Anit [1.1K]
\bf \begin{array}{cccccclllll}&\\
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\&\\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\&\\
y&=&{{ k}}&\cdot&x&\\
&\\
&&  y={{ k }}x&\\
\end{array}& \\\\\\
\textit{we know that }
\begin{cases}
y=12\\
x=1.2
\end{cases}\implies y=kx\implies 12=k\cdot 1.2

solve for "k" to find "k", or the "constant of variation"
6 0
4 years ago
Read 2 more answers
A store charges 32% extra for credit items. if the cash price is $1100, what is the credit price?​
Savatey [412]

Answer:

$1452

Step-by-step explanation:

CP=1100*1.32=$1452

6 0
3 years ago
mr sanchez owns a square field. the side lengths are 0.9 kilometers. there are 1980 prairie dog burrows in the field. what is th
nata0808 [166]
Density is the measurement of the amount of mass per unit of volume. 
In this case we should calculate the density of prairie dog burrows on a square field. This is a surface charge density.It is defined as the total amount of units q per km^2.
to calculate<span> the </span>density of prairie dog burrows, we should divide the total number of  prairie dog burrows in the field <span>by the size of the field. Thus,
</span><span>
 </span>prairie dog <span>burrows in square kilometers= number of dog burrows/ size of the field

size of the field=0.9*0.9=900*900=180000m^2
1980/180000</span><span> m^2= 0.011 dog burrows in square meter 
11 dogs in square kilometer</span>
5 0
3 years ago
Expand and simplify (x+5)(x-2)
neonofarm [45]

Answer:

{x}^{2}  + 3x  - 10

Step-by-step explanation:

(x + 5)(x - 2)

utilise the Foil method to expand brackets:

F - mulply the first terms (x and x)

O - multiply the outside terms ( x and -2)

I - multiply the inside terms (5 and x)

L - multiply the last terms (5 and -2)

Then add them as following:

{x}^{2}   - 2x + 5x - 10

Then combine like terms:

{x}^{2}  + 3x - 10

6 0
3 years ago
Read 2 more answers
The picture shows a blue rectangle split into 6
tangare [24]

Answer:

what is the answer?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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