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Pani-rosa [81]
3 years ago
9

Anyone would like to do this im so bad at math lm(a)o you will get brainliest if you do this correctly

Mathematics
2 answers:
crimeas [40]3 years ago
5 0

Answer: ok 20.51

Step-by-step explanation:

Maru [420]3 years ago
4 0

Answer:

1.548

Step-by-step explanation:

You might be interested in
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
3 years ago
Which is equivalent to (-2ab^3) (-3a^2b^5)
Artemon [7]

Answer:

6 a^3 b^8

Hope That Helps!


3 0
3 years ago
Which number line shows a fraction equivalent to 4.5?
Alchen [17]
The forth picture is the one that represents 4.5
3 0
3 years ago
Read 2 more answers
Can someone please help me out thankss
Tamiku [17]

Answer:

3x +5x =90 +30

8x =120

x =15

6 0
3 years ago
The distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 6 inche
Iteru [2.4K]

The <em><u>correct answer</u></em> is:

C.4.1 in

Explanation:

We will use a proportion for this problem.

In the first ratio, we have 6 inches: 80 pounds.  This can also be written as 6/80.

For the second ratio, we do not know the length; this is x.  The weight is 55; this gives us x/55.

This makes our proportion

6/80 = x/55

Cross multiplying, we have

6(55) = 80(x)

330 = 80x

Divide both sides by 80:

330/80 = 80x/80

4.125 = x

This means the answer is 4.1.

6 0
3 years ago
Read 2 more answers
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