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zlopas [31]
3 years ago
5

Repaying loans help?

Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0
Call mike Dorman at the Dorman team, also known as evergreen home lones
Murljashka [212]3 years ago
5 0
Yesssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss repaying loans help.
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What is 4 1/4 -3 3/5
shutvik [7]
First make the denominators the same = 4 5/20 - 3 12/20. Then make them improper fractions= 85/20-72/20= 13/20. Since that is already simplified the answer is 13/20.
5 0
4 years ago
Evaluate the function for the given value of x <br><br><br>f(n)=n^2-6n+7n at n=3 <br><br><br><br>​
vagabundo [1.1K]
F(n)=13
3^2-6(3)+7(3)=12
6 0
3 years ago
The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou
Scilla [17]

Answer:

a) correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2  surgeries  in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as\sigma^2 = mean = 6.2

hence, standard deviation is given as \sqrt{6.2} = 2.48998

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2  surgeries  in a given day is

P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)

                 = \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}

                 = 0.002029 + 0.012582+ 0.039006

                 = 0.053617

                = 0.0536

7 0
3 years ago
What's the part of an expressions that are added or subtracted
kondor19780726 [428]
We can add or subtract integer. We can also subtract like terms.
8 0
3 years ago
PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!
irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem.  So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor.  The quotient is (x-6) and the remainder is 13 according to the problem.  So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13.  That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get \frac{x^3}{13} we cannot reduce it so it is not a fraction so 13 is not a factor of P

None of these is the right option.

4 0
3 years ago
Read 2 more answers
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