Answer:
5 months
Step-by-step explanation:
Given
![c = 30m + 50](https://tex.z-dn.net/?f=c%20%3D%2030m%20%2B%2050)
![c = 20m + 100](https://tex.z-dn.net/?f=c%20%3D%2020m%20%2B%20100)
Required [Missing from the question]
At what month will the cost be equal
To do this, we equate both expressions
![c = c](https://tex.z-dn.net/?f=c%20%3D%20c)
This gives:
![30m + 50 = 20m + 100](https://tex.z-dn.net/?f=30m%20%2B%2050%20%3D%2020m%20%2B%20100)
Collect like terms
![30m - 20m = 100 - 50](https://tex.z-dn.net/?f=30m%20-%2020m%20%3D%20100%20-%2050)
![10m = 50\\](https://tex.z-dn.net/?f=10m%20%3D%2050%5C%5C)
Solve for m
![m = \frac{50}{10}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B50%7D%7B10%7D)
![m = 5](https://tex.z-dn.net/?f=m%20%3D%205)
Answer:
(24, 224 ) i.e. 24 basketball and 224 footballs
Step-by-step explanation:
<em>Basketball :</em>
uses 4 ounces of foam
20 minutes of labor
profit = $2.50
<em>Football :</em>
uses 3 ounces of foam
30 minutes of labor
profit = $2
Manufacturer has :
768 ounces of foam , 120 labor hours per week,
<u>using the simplex method to determine the optimal production schedule so as to maximize profits </u>
lets assume
x = number of basketball
y = number of footballs
maximize = 2.5 x + 2y from a linear programming problem
attached below is the detailed solution
The answer is -3. it is the only way to make the 6 negative