Can you please help?

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set. (

algol13

Answer:

its correct answer is

{y}

7 0

3 years ago

Dimitri is helping to plan the school talent show. Each performer for the talent show has 7 minutes for his or her performance,

Kaylis [27]

15 performances can be accommodated

Solution:

Given that,

Each performer for the talent show has 7 minutes for his or her performance

The introduction for the talent show is 25 minutes long

The entire show including the introduction, will last 130 minutes

Thus the remaining time for performances is:

Performance time = 130 minutes - 25 minutes

Performance time = 105 minutes

To find, the number of performances, divide the 105 by 7 minutes

$Number\ of\ performances = \frac{105}{7} = 15$

Thus 15 performances can be accommodated

5 0

4 years ago

A baby cardinal weighs about 4.3 grams at birth. After 4 days it is 3.4 times as heavy. How much does it weigh after 4 days?

Mashutka [201]

It would be 14.62 I thinks

8 0

3 years ago

renaldo catches the bus at 4:00 pm to ride 3.2 miles from his house to the dentists office. he arrives at 4:30 pm, for a one hou

Darina [25.2K]

we know that speed = distance/time

so renaldo speed = 3.2/0.5 = 6.4miles/hr (since time taken is 1/2 hr)

now after 1 hr of his appoinment i.e at 5:30pm he took bus whose speed is same as before i.e 6.4 miles/hr

now time taken to cover this 4.8 miles = 4.8/6.4 = 3/4 hr (since time = distance /speed )

3/4 hr = 3/4 * 60 = 45 minutes

so he reached at 6:15pm . so he will be on time.

6 0

4 years ago

triangle ABC is Isosceles CA and CB are equal AB is parallels to the x- axis. Work out the coordinate of A. Given that BC=5cm wo

BabaBlast [244]

Answer:

The perimeter of the triangle ABC is 17 cm.

Step-by-step explanation:

Consider the Isosceles triangle ABC.

The sides CA and CB are equal with measures, 5 cm.

The base angles are assumed to be x° each. Hence, the angle ACB is 2x°.

The altitude CP divides the base AB into two equal halves and the angle ACB is also cut into halves.

Consider the right angled triangle ACP.

The sum of all the angles in a triangle is 180°.

Determine the value of x as follows:

x° + x° + 90° = 180°

2x° = 90°

x° = 45°

Compute the length of side AP as follows:

$cos\ 45^{0}=\frac{AP}{CA}$

$\frac{1}{\sqrt{2}}=\frac{AP}{5}$

$AP =\frac{5}{\sqrt{2}}\\\\AP=3.5$

Then the length of side AB is:

AB = AP + PB

= 3.5 + 3.5

= 7 cm

The perimeter of triangle ABC is:

Perimeter = AB + CA + CB

= 7 + 5 + 5

= 17

Thus, the perimeter of the triangle ABC is 17 cm.

8 0

3 years ago