Let

be a probability that i-th light fails, where i=1,2,3. Then,

is the probability that i-th light remain bright.
<span>If the lights fail independently of each other, the probability that a string of lights will remain bright for two years is:
</span>

.
It should be 8 if it is 5-5 which gives you 0.
Or it could be (5x5)-5=20+8=28.
Graph 1 I’m pretty sure. I’m sorry if it’s wrong have a nice day
3/4+7/10 common denominator is 20
3/4+7/10
=5•3/20 +2•7/20
=15/20 +14/20
=29/20
=1 9/20