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Degger [83]
2 years ago
9

Determine the center and radius: x2 + y2 - 10x + 8y -8 = 0​

Mathematics
1 answer:
Kipish [7]2 years ago
7 0

So our equation currently is ⇒ x^2+y^2-10x+8y-8 = 0

<u>Let's first move all the constant to one side and group 'like variables' together</u>:

      (x^2-10x)+(y^2+8y) = 8

<u>Now lets complete the square of both equations</u>

    (x^2-10x+25)+(y^2+8y +16) = 8 + 25 + 16\\(x-5)^2+(y+4)^2 = 49\\(x-5)^2+(y+4)^2 = 7^2

<u><em>Now we know the circle's general equation format is</em></u>:

   ⇒(x-h)^2+(y-k)^2 = r^2

  • (h, k) ⇒ coordinate of the center of the circle
  • r ⇒ length of radius of circle

<u>Thus the radius of the circle is 7</u>

<u></u>

Hope that helps!

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Cosines: cos A = b/c, cos B = a/c.

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Step-by-step explanation:

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