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erastovalidia [21]
3 years ago
12

This is worth 15 points please help!

Mathematics
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

D i mean i guess you try to salve on a piece of paper

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Express 4 4/9 as an improper fraction. Example please.
miskamm [114]
Simple...

you have: 4 \frac{4}{9}

To make this into an improper fraction-->>

1.) Multiply whole number by denominator

2.)Add the number you got plus the numerator

3.) Use the original denominator to finish your improper fraction

Example: 4\frac{4}{9}

4*9=36

36+4=40

\frac{40}{9}

Thus, your answer.
3 0
3 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
snow_lady [41]

If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB.  ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

CD = 4 cm (given) so AC = 2(4 cm) = 8 cm

Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>

Lastly, look at ΔBHD.  Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.

BD = 12 cm, so HD = \frac{12}{2}cm = 6 cm

Answer: 6 cm



8 0
3 years ago
Read 2 more answers
A regular hexagon rotates counterclockwise about its center. It turns through angles greater than 0° and less than or equal to 3
Bogdan [553]
Hey there Caleb!

To start of, the sentence was clear on that it said . . . 

\boxed{A \ regular \ hexagon \ rotates \ counterclockwise \ about \ its &#10; \ center }

The statement listed above is the (key) point. We need to keep this in mind.

So, now that we know this.

We would use the mathematic (Ф)

So,sense we know that a (hexagon) had it's (6) shapes, we would do . . . 

Ф = 360° : 6 = 60°

Your correct answer to this question would be . . . 

\boxed{\boxed{60}}

Hope this helps.
~Jurgen
5 0
3 years ago
Read 2 more answers
2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One
Stells [14]

y'=(t+y)^2-1

Substitute u=t+y, so that u'=y', and

u'=u^2-1

which is separable as

\dfrac{u'}{u^2-1}=1

Integrate both sides with respect to t. For the integral on the left, first split into partial fractions:

\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1

\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt

\dfrac12(\ln|u-1|-\ln|u+1|)=t+C

Solve for u:

\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C

\ln\left|1-\dfrac2{u+1}\right|=2t+C

1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}

\dfrac2{u+1}=1-Ce^{2t}

\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}

u=\dfrac2{1-Ce^{2t}}-1

Replace u and solve for y:

t+y=\dfrac2{1-Ce^{2t}}-1

y=\dfrac2{1-Ce^{2t}}-1-t

Now use the given initial condition to solve for C:

y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}

so that the particular solution is

y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}

3 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
const2013 [10]

Function:

f(x) = 30x (75%) + 1

Bacteria after 2 hours:

10,890 bacteria

4 0
3 years ago
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