Answer:
1/x+2
Step-by-step explanation:
To find the inverse of the function, try switching the x value with the y value or function value
something like: x=1/g(x)-2
then, just manipulate the equation so that g(x) is by itself again, but this time, since it is an inverse, it's denoted as g-1(x)
x=1/g-1(x)-2
x+2=1/g-1(x)
(g-1(x))(x+2)=1
g-1(x)=1/(x+2)
Answer:
-2x² + 15
Step-by-step explanation:
Step 1: Add like terms
4x² - 6x² = -2x²
-10x + 10x = 0
3 + 12 = 15
Step 2: Rewrite
-2x² + 15
To find the area of a circle you do pi (3.14) multiplied by the radius squared.
The radius is half of the diameter: 11 / 2 = 5.5in
The radius squared is 5.5^2 = 30.25
Then take the squared radius and multiply that by pi 30.25 * 3.14 = 94.985
So the area of the circle is about 94. 99 in.
Hope this helped! Mark as Brainliest please! :)))
Scale factor is always (new/original)
so it depends which rectangle came first. if it started as large and was dilated to the smaller one, then the ratio is (.5/2.5) which simplifies to 1/5 or 0.2.
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
