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3 years ago

These figures are congruent. What series of transformations moves pentagon

Mathematics

2 answers:

Sonja [21]3 years ago

8 0

Answer:

the answer is C

Step-by-step explanation:

rosijanka [135]3 years ago

6 0

Answer: C

Step-by-step explanation:

It would have to be a translation and another translation because the preimage of the figure is the same orientation as the image therefore it can't have a rotation or reflection included in it so the answer would be C. Hope this helps :)!

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Find the missing side.

astra-53 [7]

Answer:

B: 19.3

Step-by-step explanation:

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3 years ago

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A circle is centered at H(4, 0) and has a radius of 10. Where does the point L(-2, 8) lie

Anon25 [30]

Answer:

Step-by-step explanation:

HL=√((-2-4)²+(8-0)²)=√(36+64)=√100=10=radius

so L lies on the circumference of circle.

or eq. of circle is (x-4)²+(y-0)²=10²

(x-4)²+y²=100

Put x=-2,y=8

(-2-4)²+8²=100

36+64=100

or 100=100

which is true.

Hence L lies on the circle.

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4 years ago

D.153.86in.............

Novay_Z [31]

It is D) 153.86 just find it by using the formula

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3 years ago

f(x) = 20(1.5)x. Let your dependent variable in the function be y. Write the function that models the independent variable in te

mars1129 [50]

Answer:

$x=log_{1.5}(\frac{y}{20})$

Step-by-step explanation:

Considering the function:

$f(x) = 20\, (1.5)^x$

The independent variable is "x" and we are asked to model it in terms of the variable "y":

$f(x) = 20\, (1.5)^x\\y=20\, (1.5)^x$

Then, in order to solve for x (which resides in the exponent), we need to use the logarithm function.

Since the base of the exponent is 1.5, we need to use the logarithm base 1.5, to lower that exponent "x":

$y=20\, (1.5)^x\\\frac{y}{20} =(1.5)^x\\log_{1.5}(\frac{y}{20}) =x\\x=log_{1.5}(\frac{y}{20})$

6 0

3 years ago

Asap answer pls-----------

marissa [1.9K]

Answer:

$y=\frac{4}{5}x-\frac{18}{5}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0).

<u>1) Determine the slope (m)</u>

$m=\frac{y_2-y_1}{x_2-x_1}$ where two points on the line are $(x_1,y_1)$ and $(x_2,y_2)$

In the graph, the points (-3,-6) and (2,-2) are plotted clearly, so we can use these to help us find the slope. Plug them into the equation:

$m=\frac{-6-(-2)}{-3-2}\\m=\frac{-6+2}{-3-2}\\m=\frac{-4}{-5}\\m=\frac{4}{5}$

Therefore, the slope of the line is $\frac{4}{5}$ . Plug this into $y=mx+b$ :

$y=\frac{4}{5}x+b$

<u>2) Determine the y-intercept (b)</u>

$y=\frac{4}{5}x+b$

Typically, given a graph, we could look at where exactly the line crosses the y-axis to determine b. However, because it appears ambiguous on this graph, we must solve it algebraically.

Plug in one of the given points (2,-2) and solve for b:

$-2=\frac{4}{5}(2)+b\\-2=\frac{8}{5}+b$

Subtract $\frac{8}{5}$ from both sides to isolate b

$-2-\frac{8}{5}=\frac{8}{5}+b-\frac{8}{5}\\-\frac{18}{5} =b$

Therefore, the y-intercept of the line is $-\frac{18}{5}$ . Plug this back into $y=\frac{4}{5}x+b$ :

$y=\frac{4}{5}x+(-\frac{18}{5})\\y=\frac{4}{5}x-\frac{18}{5}$

I hope this helps!

8 0

3 years ago