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3 years ago

5

A couple that already has two daughters wants to have another child. the couple is hoping for a son. what is the probability tha

t the couple\'s third child will be a boy? record your answer as a percentage.

1 answer:

Natali [406]3 years ago

8 0

Answer: 50%

Explanation:

A child is either a boy or a girl
P(a boy) = 1/2 = 50%

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The midpoint of AB is M(-3, 0). If the coordinates of A are (1,-4), what are the coordinates of B?

zimovet [89]

Using the given information, the coordinates of B are (-7, 4)

<h3>Midpoint of a Line </h3>

From the question, we are to determine the coordinates of B.

Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is

((x₁+x₂)/2, (y₁+y₂)/2)

From the given information,

The midpoint of AB is M(-3, 0)

and

The coordinates of A are (1,-4)

Let the coordinates of B be (x₁, y₁)

Then,

-3 = (1 + x₁)/2

-6 = 1 + x₁

x₁ = -6 -1

x₁ = -7

Also,

0 = (-4 + y₁)/2

0 = -4 + y₁

y₁ = 0 + 4

y₁ = 4

Hence, the coordinates of B are (-7, 4)

Learn more on Midpoint of a line here: brainly.com/question/18315903

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7 0

2 years ago

Write in scientific notation: .0000604

NISA [10]

Step-by-step explanation:

Scientific notation : 6.04 * 10^-5.

8 0

3 years ago

Read 2 more answers

Lin ran 2 3/4 miles in 2/5 of an hour, Noah ran 8 2/3 miles in 4/3 of an hour, how far would Lin run in 1 hour?

Marizza181 [45]

Answer:

$6\frac{7}{8}\ miles$

Step-by-step explanation:

Given that Lil's distance in 2/5 hrs is 2 3/4hrs

-Let x be the distance ran in 1 hr.

#We equate and cross multiply to solve for x as follows:

$\frac{2}{5}\ hrs=2\frac{3}{4}\\1\ hr=x\\\\\therefore x=2\frac{3}{4}/\frac{2}{5}\\\\=6\frac{7}{8}\ miles$

Hence, Lil can run 6 7/8 miles in 1 hr.

5 0

3 years ago

What is the solution to 1< 25-4x<19?

koban [17]

Hope this helps

Hope you have a good day

4 0

3 years ago

weeeeeb [17]

Answer:

2x + y = -4

Step-by-step explanation:

standard form of equation of straight line is

ax+by = c

that is terms containing x and y should be on LHS and constant term should be on RHS

______________________________________________

Given equation

y + 1 = - 2x - 3

lets bring -2x on LHS ,

add 2x on lHS and RHS

y + 1 + 2x = - 2x - 3 + 2x

=> y + 1 + 2x = -3

on lHS, 1 is there which constant term lets bring it on RHS

subtract 1 from both sides

y + 1 + 2x - 1= -3 -1

y + 2x = -4

rearranging it

2x + y = -4 (Answer)

8 0

3 years ago