Answer:
ntersecting lines DA and CE.
To find:
Each pair of adjacent angles and vertical angles.
Solution:
Adjacent angles are in the same straight line.
Pair of adjacent angles:
(1) ∠EBD and ∠DBC
(2) ∠DBC and ∠CBA
(3) ∠CBA and ∠ABE
(4) ∠ABE and ∠EBD
Vertical angles are opposite angles in the same vertex.
Pair of vertical angles:
(1) ∠EBD and ∠CBA
(2) ∠DBC and ∠EBA
Answer:
Please try writing your question properly.
Step-by-step explanation:
I will help you in solving it.
Answer:
x ≈ 25.5°
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] tanθ = opposite over adjacent
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle θ = <em>x</em>°
Opposite Leg = 10
Hypotenuse = 21
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [tangent]: tanx° = 10/21
- Inverse trig: x° = tan⁻¹(10/21)
- Evaluate: x = 25.4633°
- Round: x ≈ 25.5°
Answer:
C
Step-by-step explanation:
