Answer:
0.6 cups of sugar and 1.25 cups of chocolate chips
Step-by-step explanation:
We can begin to solve this problem with a simple proportion:
= 
= 
(x = the new # of sugar y = new # of chocolate chips)
In order to keep everything proportional, we must abide by the scale factor shown with the the flour.
Basically, if we're going to use three times the amount of flour we actually need, then we need to triple all our other ingredients.
We can see that the scale factor is one half, so
x = 1.2 * 0.5
and
y = 2.5 * 0.5
This means that:
x = 0.6
y = 1.25
This means that he has to use 0.6 (or 3/5) cups of sugar and 1.25 (or 9/8) cups of chocolate chips.
Step-by-step explanation:
sunaina's alona work=
1/6-1/10
10-6/60
4/60
1/15
therefore sunaina can alone do the work in 15 days
Using the normal distribution, it is found that:
- 3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
- 3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
- 4 - a) The 25th percentile for the math scores was of 71.6 inches.
- 4 - b) The 75th percentile for the math scores was of 78.4 inches.
<h3>Normal Probability Distribution
</h3>
In a <em>normal distribution </em>with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
Question 3:
- The mean is of 73 inches, hence
.
- The standard deviation is of 3 inches, hence
.
Item a:
The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.
The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
Item b:
The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.
The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
Question 4:
- The mean score is of 75, hence
.
- The standard deviation is of 5, hence
.
Item a:
The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.
The 25th percentile for the math scores was of 71.6 inches.
Item b:
The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.
The 75th percentile for the math scores was of 78.4 inches.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213
Answer:
17x+5
Step-by-step explanation:
Simplify the equation
