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3 years ago

Rewrite the equation in standard form and identify a, b, and c. 2x^2 + 6x - 9 = 3x^2 - 11x - 7

2 answers:

8 0

2x^2 + 6x - 9 = 3x^2 - 11x - 7

Subtract 2x^2 from both sides
6x - 9 = x^2 - 11x - 7

Substract 6x from both sides
-9 = x^2 - 17x - 7

Add 9 to both sides
0 = x^2 - 17x + 2

a = 1
b = -17
c = 2

Ostrovityanka [42]3 years ago

3 0

$2x^2 + 6x - 9 = 3x^2 - 11x - 7\\
x^2-17x+2=0\\
a=1\\
b=-17\\
c=2$

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4 years ago

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Step-by-step explanation:

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3 years ago

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lorasvet [3.4K]

Answer:

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Step-by-step explanation:

To complete the square, we first have to get our equation into $ax^2 + bx = c$ form.

First we add 16x to both sides:

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And now we subtract 62 from both sides.

$x^2 + 16x = -62$

We now have to add $(\frac{b}{2})^2$ to both sides of the equation. b is 16, so this value becomes $(16\div2)^2 = 8^2 = 64$ .

$x^2 + 16x + 64 = -62+64$

We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because $8\cdot8=64$ and $8+8=16$ .

$(x+8)^2 = -62 + 64$

We can now take the square root of both sides.

$x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}$

We can now isolate x on one side by subtracting 8 from both sides.

$x = \pm\sqrt{2} - 8$

So our solutions are

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3 years ago

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Answer:

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Step-by-step explanation:

Formula: (midpoint)

Let the point A(x , y) be the midpoint of CD.

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$y=\frac{x_C + y_D}{2} =\frac{4+(-2)}{2} =\frac{2}{2} =1$

Then

A(-1 , 1)

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2 years ago

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GuDViN [60]

Answer:

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