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3 years ago

Rewrite the equation in standard form and identify a, b, and c. 2x^2 + 6x - 9 = 3x^2 - 11x - 7

2 answers:

8 0

2x^2 + 6x - 9 = 3x^2 - 11x - 7

Subtract 2x^2 from both sides
6x - 9 = x^2 - 11x - 7

Substract 6x from both sides
-9 = x^2 - 17x - 7

Add 9 to both sides
0 = x^2 - 17x + 2

a = 1
b = -17
c = 2

Ostrovityanka [42]3 years ago

3 0

$2x^2 + 6x - 9 = 3x^2 - 11x - 7\\
x^2-17x+2=0\\
a=1\\
b=-17\\
c=2$

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If $25, 000 is invested into an account paying 4.5% per year, compounded quarterly, how much money can be withdrawn from the acc

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The money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

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The formula for compound interest is given as;

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2 years ago

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.