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marysya [2.9K]
3 years ago
13

If f(x)=2x^2+3 and g(x)=x^2-7 find (f+g)(x)

Mathematics
1 answer:
Ivan3 years ago
8 0

Answer:

Answer is (f + g)(x) = 3x^2 - 4

Step-by-step explanation:

Given,

f(x) = 2x^2 + 3

g(x) = x^2 - 7

To find : (f + g)(x)

(f + g)(x) = f(x) + g(x)

             = (2x^2 + 3) + (x^2 - 7 )

             = 2x^2 + x^2 + 3 - 7

(f + g)(x) = 3x^2 - 4

Hence we get (f + g)(x) = 3x^2 - 4

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Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6
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On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
3y=2x-6                    Divide by 3 in both sides to isolate y
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The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b                 Substitute the given point and the previous slope found
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The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.


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