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kow [346]
2 years ago
7

Below are two parallel lines with a third line intersecting them. x= ??°

Mathematics
1 answer:
rodikova [14]2 years ago
6 0

Answer:

x = 53

Step-by-step explanation:

x = 53 because they are alternate exterior angles

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Sergio039 [100]
Divide across and just bring down the numbers
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If the needle below is spun twice and the letters are recorded both times , which of the following would be the probability it w
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2/3 is the correct answer
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One of the rows in the table has an error and does not have the same ratio as the other rows. Which explains how to correct the
hram777 [196]
<span>Row 1 3 ft  91.44 cm
The ratio is 91.44 cm/ 3 ft = 30.48 cm/ft

</span><span>Row 2 6 ft 172.88 cm
The ratio is 172.88 cm / 6 ft = 28.81 cm/ft which ius not the same as 30.48 cm/ft.

</span><span>Row 3 7 ft 213.36 cm
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<span>The ratio is 213.36 cm/ 7 ft = 30.48 cm/ft, which is the same as the first ratio.

Since 2 rows have the ratio 30.48 cm/ft, this ratio is correct. The ratio 172.88 cm / 6 ft is incorrect.

6 ft * 30.48 cm/ft = 182.88 cm

Answer: </span>
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4 0
3 years ago
Read 2 more answers
What is the 8.356 rounded to the nearest hundredth
rodikova [14]

Answer:

8.356 rounded to the nearest hundredth=8.360

5 0
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Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
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