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Artyom0805 [142]
3 years ago
15

What is wrong in the drawing? How can you make this work Correct?

Mathematics
1 answer:
Kryger [21]3 years ago
4 0
The picture is completely black I’m not sure if that’s what you’re trying to fix but I think you didn’t uploads it correctly.
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Find the diagonal of a rectangular frame which measures 77 in. by 36 in.
quester [9]

Answer:

Diagonal of a rectangular frame = 85 inch

Step-by-step explanation:

Given:

Length of rectangle = 77 inch

Width of rectangle = 36 inch

Find:

Diagonal of a rectangular frame

Computation:

Diagonal of a rectangle = √l² + b²

Diagonal of a rectangular frame = √77² + 36²

Diagonal of a rectangular frame = √5,929 + 1,296

Diagonal of a rectangular frame = √7,225

Diagonal of a rectangular frame = 85 inch

7 0
3 years ago
Philip wants to know the weight of a book to within half a gram. His weighing scales only weigh to within 10 grammes.
Andrei [34K]

Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step explanation:

8 0
3 years ago
You have a 10 by 24 piece of cardboard. You are going to cut squares of equal size from each corner, and fold up the sides to ma
densk [106]

Answer:

  10-2x

Step-by-step explanation:

If x is the length of one side of the square, the total width of the cardboard has two squares cut from it. The amount of width remaining is the width of the box. Since the original width of the cardboard is 10, the width of the box is ...

  10 -2x

8 0
2 years ago
Which number is prime?<br> 85<br> 49<br> 70<br> 31
Citrus2011 [14]

Answer: 31 is a prime number because only 1 times itself equals 31. no other two factors equal 31 as a product.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Quadrilateral CDEF is dilated by a scale factor of į to form quadrilateral C'D'E'F'.
Kobotan [32]

Given:

CDEF is dilated by a scale factor of \dfrac{3}{4} to form the quadrilateral C'D'E'F'.

To find:

The measure of side E'F'.

Solution:

If a figure is dilated by a scale factor of k, then the side of dilated figure is k times of corresponding side of original figure.

CDEF is dilated by a scale factor of \dfrac{3}{4} to form the quadrilateral C'D'E'F'. So,

E'F'=\dfrac{3}{4}\times EF

From the given figure it is clear that EF=12. So,

E'F'=\dfrac{3}{4}\times 12

E'F'=9

Therefore, the measure of side E'F' is 9 units.

7 0
2 years ago
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