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Orlov [11]
3 years ago
9

A box contains 2 red marbles, 3 white marbles, 4 green marbles, and 1 blue marble find the probability of selecting a white marb

le in the first draw and a red marble in the second draw
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

Answers

Selecting a green marble on the second

draw if the first marble is blue.

Answer:

Selecting a white marble on the first

draw and red marble on the second

draw.

Answer:

Selecting a red marbles on both draws.

Answer:

Selecting a red or white on the first

draw and green or blue on the second

draw.

Answer:  

Selecting a white marble on the first

draw and a white or blue on the second

draw.

Step-by-step explanation:

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Sarah is doing research on the average age of first-year resident physicians. She wants her estimate to be accurate to within 1
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Answer: The number of first-year residents she must survey to be 95% confident= 263

Step-by-step explanation:

When population standard deviation (\sigma)  is known and margin of error(E) is given, then the minimum sample size (n) is given by :-

n=(\dfrac{z^*\sigma}{E})^2, z* = Two-tailed critical value for the given confidence interval.

For 95% confidence level , z* = 1.96

As, \sigma = 8.265, E = 1

So, n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]

Hence, the number of first-year residents she must survey to be 95% confident= 263

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3 years ago
What is -c - d <br> c = -3 and d = -6
Yakvenalex [24]

Answer:

-3

Step-by-step explanation:

-(-3) = 3

-(-6) = 6

-3 - (-6) = 3

-c - d

c = -3

-3 - d

d = -6

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8 0
4 years ago
Read 2 more answers
If cosine theta equals negative square root of three over two and pi over two less than theta less than pi, what are the values
Natalka [10]
<h2>Answer:</h2>

The values of sinθ and tanθ are:

\sin \theta=\dfrac{1}{2}

and

\tan \theta=-\dfrac{1}{\sqrt{3}}=-\dfrac{\sqrt{3}}{3}

<h2>Step-by-step explanation:</h2>

It is given that:

\cos \theta=-\dfrac{\sqrt{3}}{2}

where

\dfrac{\pi}{2}

i.e. the angle θ lie in the second quadrant.

Also, we know that in the second quadrant sine and cosecant function is positive.

whereas cosine,secant, tangent and cotangent functions are negative.

Now, we know that:

\cos (\dfrac{5\pi}{6})=-\dfrac{\sqrt{3}}{2}

i.e. here

\theta=\dfrac{5\pi}{6}

Hence, we have:

\sin (\theta)=\sin (\dfrac{5\pi}{6})\\\\i.e.\\\\\sin \theta=\dfrac{1}{2}

Also,

\tan \theta=\dfrac{\sin \theta}{\cos \theta}\\\\i.e.\\\\\tan \theta=\dfrac{\dfrac{1}{2}}{\dfrac{-\sqrt{3}}{2}}\\\\i.e.\\\\\tan \theta=\dfrac{1}{-\sqrt{3}}\\\\i.e.\\\\\tan \theta=-\dfrac{1}{\sqrt{3}}

Now, on rationalizing we have:

\tan \theta=-\dfrac{\sqrt{3}}{3}

7 0
4 years ago
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