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3241004551 [841]
3 years ago
5

Sarah is doing research on the average age of first-year resident physicians. She wants her estimate to be accurate to within 1

year. From past studies, she knows the population standard deviation is 8.265. How many first-year residents must she survey to be 95% confident?
Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer: The number of first-year residents she must survey to be 95% confident= 263

Step-by-step explanation:

When population standard deviation (\sigma)  is known and margin of error(E) is given, then the minimum sample size (n) is given by :-

n=(\dfrac{z^*\sigma}{E})^2, z* = Two-tailed critical value for the given confidence interval.

For 95% confidence level , z* = 1.96

As, \sigma = 8.265, E = 1

So, n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]

Hence, the number of first-year residents she must survey to be 95% confident= 263

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liubo4ka [24]
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  • m<4=?

Both are supplementary angles.

\\ \rm{:}\twoheadrightarrow m

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3 years ago
Babies born after a gestation period of 32-35 weeks have a mean weight of 2700 grams and a standard deviation of 700 grams, whil
Nutka1998 [239]

Answer:

The 33 week gestation period baby has the higher z-score, so he weighs more relative to other babies of the same gestation period.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Who weighs more relative to other babies of the same gestation period?

Whoever has the higer z-score

33 - week baby.

Babies born after a gestation period of 32-35 weeks have a mean weight of 2700 grams and a standard deviation of 700 grams. A 33-week gestation baby weighs 2950 grams.

We have to find z when \mu = 2700, \sigma = 700, X = 2950. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2950 - 2700}{700}

Z = 0.357

40-week baby

Mean weight of 3000 grams and a standard deviation of 490 grams. 40-week gestation baby weighs 3150 grams.

We have to find Z when \mu = 3000, \sigma = 490, X = 3150. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{3150 - 300}{490}

Z = 0.306

The 33 week gestation period baby has the higher z-score, so he weighs more relative to other babies of the same gestation period.

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Answer:

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Answer:

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Step-by-step explanation:

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